How to store value for multiple iteration

a= 10;
b= [1 0 0 0 1 0 1 0 1 0;1 1 0 0 1 0 1 0 1 1;1 0 1 0 1 0 1 1 1 0;1 1 1 1 1 0 1 0 1 0;1 0 1 0 1 0 1 0 1 0 ];
e= [0.05 0.08 0.2 0.4];
iteration= 1;
x= zeros(1,1);

g= eye(10);
G= [g;b];

for t=1 : iteration
    s=zeros(4,1);
    offset=1;
    for u=e(1:length(e))
        F = G ;
        for i=1:15
            if(rand < u)
                F(i,:) = 0;
            end
        end
        soup=zeros(1,a);
        for k = 1 : 15
            FD = max( F(k,:)-soup, 0) ;
            if( sum(FD) == 1)
                [MaxValue Idx] = max(FD) ;
                soup(Idx) = 1 ;
            end
        end
        h =sum(soup) ;
        s(offset,:)=h;
        offset=offset+1;
    end
end

Now I want to change the value of “iteration” and want to make it 1000; For, each “iteration”

I want to count how many values of “s” are equal to “a”. Suppose, for each “iteration” the number of values in “s” that are equal to “a” is “T”(Let) Then I want to divide “T” by length(e) for each iteration. Suppose that value for each iteration is V (Let) Then I want to get the average value of V for total thousand “iteration” Example: Let, for 2 iteration, the number of values in “s” that are equal to “a” is 3,2 So,

For iteration=1, V=3/length(e)=3/4=0.75
     For iteration = 2, V=2/length(e)=0.5
So,  average value of V for two iteration = (0.75+0.5) / 2 = 0.625
I tried for several times but unable to do so.

Matlab experts please need your help and suggestion.

Answer 1

[A Jenkins]

a= 10;
b= [1 0 0 0 1 0 1 0 1 0;1 1 0 0 1 0 1 0 1 1;1 0 1 0 1 0 1 1 1 0;1 1 1 1 1 0 1 0 1 0;1 0 1 0 1 0 1 0 1 0 ];
e= [0.05 0.08 0.2 0.4];
iteration= 1000;
x= zeros(1,1);
g= eye(10);
G= [g;b];
V=zeros(1,iteration);
for t=1 : iteration
    s=zeros(4,1);
    offset=1;
    for u=e(1:length(e))
        F = G ;
        for i=1:15
            if(rand < u)
                F(i,:) = 0;
            end
        end
        soup=zeros(1,a);
        for k = 1 : 15
            FD = max( F(k,:)-soup, 0) ;
            if( sum(FD) == 1)
                [MaxValue Idx] = max(FD) ;
                soup(Idx) = 1 ;
            end
        end
        h =sum(soup) ;
        s(offset,:)=h;
        offset=offset+1;
    end
    T=sum(s==a);
    V(t)=T/length(e);
end

avgV=mean(V)

[Eagle]

@ A Jenkins- if s=[100 x 57] matrix then i cannot find the value of V. Please need your help.

[A Jenkins]

sum() itself sums over one dimension. If you have a two dimensional matrix, you need to sum twice.

T=sum(sum(s==a))

Another option, if the dimensions of s can change:

T=sum(reshape(s,1,[])==a)