make replacements in an array

i have an array of doubles, A.

A = [0; 0; 1; 1; 0; 1];

I wish to replace all the 1's with 'yes' and the 0's with 'no'. can this be done in order to produce an output B?

B = [no; no; yes; yes; no; yes];

[Michael]

ok, in understand the whole character thing, but just say i want to add a 3rd option to the mix..

A = [1; 2; 3]

how do i get:

B = ['one '; 'two '; 'three']

?

thanks again everyone

Answer 1

[Sean de Wolski]

B must be a cell array.

A = [0; 0; 1; 1; 0; 1];
B = repmat({'no'},size(A));
B(logical(A)) = {'yes'}

Part 2

Numbs = {'one';'two';'three'}; %etc
A = [1;2;3];
B = Numbs(A)

[Michael]

i was making this way to complicated, thanks

Answer 2

[Jan]

A = [0; 0; 1; 1; 0; 1];  
C = {'no', 'yes'}
B = reshape(C(A + 1), [], 1);

But as Matt T. said: Now B is a CELL string, which is not exactly "[no; no; yes; yes; no; yes]", because this is not possible in Matlab.

Answer 3

[Matt Tearle]

You can't have a matrix of strings 'yes' and 'no', like you've shown. You can have logicals (true/false), but they will display like 1/0. You can make a cell array of strings. You can make a character array of strings by padding the 'no's with a space ('no '). Or, if you have Statistics Toolbox, you can make a nominal array.

What is your purpose in all of this?

[Michael]

basically for work i have to produce reports and there are different types of data that i look at and wanted to tag each type of data with strings. right now i just have numbers to tag them instead of character labels. this was just a simple example. there are actually 3 types of data that i tagged as 1, 2, and 3.

[Matt Tearle]

A = randi(3,1,10)

B = nominal(A,{'one','two','three'},1:3)

(if you have Stats TB)