Why are the results of the size function different from the whos function Size?
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Why are the results of the size function different from the whos function Size?
Here is an example:
>> excelstring = strfind('ABC DUMP.txt','.xls')
excelstring =
[]
>> size excelstring
ans =
1 11
>> whos excelstring Name Size Bytes Class Attributes
excelstring 0x0 0 double
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James Tursa
le 15 Juin 2011
Doing this:
size excelstring
Is equivalent to doing this:
size('excelstring')
Whenever you invoke a function without the parens, the remainder of your inputs are taken to be literal string(s).
1 commentaire
Matt Fig
le 15 Juin 2011
As described here:
http://www.mathworks.com/help/techdoc/ref/syntax.html
This is called command-function duality.
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the cyclist
le 15 Juin 2011
Because the syntax for what you wanted is
>> size(excelstring)
Looks like your syntax is giving the size of the string 'excelstring', rather than that of the variable named excelstring.
1 commentaire
Chirag Gupta
le 15 Juin 2011
To explain further, size excelstring is equivalent to asking MATLAB to compute size('excelstring').
MATLAB takes the arguments as strings if they are not passed in parenthesis ()
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