Problem 1307. RPN Calculator for simple arithmetic expressions

Created by Muthu Annamalai

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{"relationships":[{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/document","targetMode":"","relationshipId":"rId1","target":"/matlab/document.xml"},{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/output","targetMode":"","relationshipId":"rId2","target":"/matlab/output.xml"}],"parts":[{"partUri":"/matlab/document.xml","relationship":[],"contentType":"application/vnd.mathworks.matlab.code.document+xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<w:document xmlns:w=\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\"><w:body><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Reverse-Polish-Notation (RPN) is a machine friendly form of calculating expressions. Example, to evaluate, (1+2)*4 + 5 - 3 you enter the sequence into the calculator as, '5 1 2 + 4 * + 3 -' and obtain the result.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>For this challenge write a RPN calculator for simple arithmetic expressions, '+','-','*','%','/'</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Note: Chosen interpretations of operators, illustrated from first few test cases, are as follows: rpn('a','b','-') is interpreted as 'a-b', while rpn('a','b','/') is interpreted as 'b/a'. and rpz('a','b','%') which is interpreted as 'b%a'.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>with operator '%' 'b % a' being mod(b,a) operator.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Following your 'stack' solution to</w:t></w:r><w:r><w:t> </w:t></w:r><w:hyperlink w:docLocation=\"http://www.mathworks.com/matlabcentral/cody/problems/1303-is-the-paranthesis-sequence-balanced\"><w:r><w:t>http://www.mathworks.com/matlabcentral/cody/problems/1303-is-the-paranthesis-sequence-balanced</w:t></w:r></w:hyperlink><w:r><w:t> try using a expression, and a value stack to work this problem.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Hint:</w:t></w:r><w:r><w:t> </w:t></w:r><w:hyperlink w:docLocation=\"http://en.wikipedia.org/wiki/Reverse_Polish_notation\"><w:r><w:t>http://en.wikipedia.org/wiki/Reverse_Polish_notation</w:t></w:r></w:hyperlink></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

Reverse-Polish-Notation (RPN) is a machine friendly form of calculating expressions. Example, to evaluate, (1+2)*4 + 5 - 3 you enter the sequence into the calculator as, '5 1 2 + 4 * + 3 -' and obtain the result.For this challenge write a RPN calculator for simple arithmetic expressions, '+','-','*','%','/'Note: Chosen interpretations of operators, illustrated from first few test cases, are as follows: rpn('a','b','-') is interpreted as 'a-b', while rpn('a','b','/') is interpreted as 'b/a'. and rpz('a','b','%') which is interpreted as 'b%a'.with operator '%' 'b % a' being mod(b,a) operator.Following your 'stack' solution to <a href = "http://www.mathworks.com/matlabcentral/cody/problems/1303-is-the-paranthesis-sequence-balanced">http://www.mathworks.com/matlabcentral/cody/problems/1303-is-the-paranthesis-sequence-balanced</a> try using a expression, and a value stack to work this problem.Hint: <a href = "http://en.wikipedia.org/wiki/Reverse_Polish_notation">http://en.wikipedia.org/wiki/Reverse_Polish_notation</a>

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Last Solution submitted on Jun 12, 2020

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Alfonso Nieto-Castanon on 1 Mar 2013

in your test suite it seems odd that rpz('a','b','-') is interpreted as 'a-b' while rpz('a','b','/') is interpreted as 'b/a' (instead of 'a/b'). Same goes for rpz('a','b','%') which is interpreted as 'b%a' instead of 'a%b'. Last, your last test case rpn(z(1),'+',z(2),'*',z(1),z(3),'-',z(4),z(5),'%','*') is plain weird... it should probably read rpn(z(1),z(2),'+',z(1),'*',z(3),'-',z(4),z(5),'%','*') instead...

Muthu Annamalai on 2 Mar 2013

Thank you for your comments; I will update the description and fix last test case.

Muthu Annamalai on 22 Mar 2013

I will retire the last test case for the problem.

Baki on 6 Nov 2016

I have an rpn solver but it only accepts strings

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rpn stack polish-notation expression evaluation

Problem 1307. RPN Calculator for simple arithmetic expressions

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Problem 1307. RPN Calculator for simple arithmetic expressions

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