Tanya, you like triangles.
These are interesting
a = sqrt(c^2-b^2);
this isn't a calculation!
test_1 a=sqrt(3) is longer than b=1
the good solution would be
a= min(sqrt(c^2 -b^2),b)
Kudos for finding this solution - it did indeed meet all the test cases, but wasn't quite what I had in mind! I will add a new test.
Return elements unique to either input
Matrix indexing with two vectors of indices
Output any real number that is neither positive nor negative
Natural numbers in string form
Find the 9's Complement
Find a Pythagorean triple
Area of an equilateral triangle
Dimensions of a rectangle
Area of an Isoceles Triangle
Is this triangle right-angled?
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