Given a vector of numbers, return true if one of the numbers is a square of one of the other numbers. Otherwise return false.
Example:
Input a = [2 3 4] Output b is true
Output is true since 2^2 is 4 and both 2 and 4 appear on the list.
Solution Stats
Problem Comments
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13 Comments
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10 older comments
Alex Feinman
on 25 Jan 2012
Another of the classic "check if MATLAB has a function that does this already" problems...
Michael Joslin
on 6 Feb 2012
What about a vector like [2 3 1]? The top solution will still return true because 1^2 is still one but it is not the square of one of the OTHER numbers.
Felix
on 12 Dec 2012
is the Str2func construct really more effective???
Is it possible that this distorts the metric a bit?
Gregoire
on 11 Apr 2014
It is currently impossible to submit a solution for this problem. The web page will never load.
Mattias
on 2 Jan 2015
The problem description states that one of the numbers has to be a square of one of the OTHER numbers. Still, the test suite tests if [1] gives true. I think [1] should give false, or that describtion be modified.
Ramoflaple
on 4 Jul 2015
Agree with Mattias. the length of input vector should be 2 or larger.
Shamma Sultan
on 30 Aug 2016
The difference between test 4 and 5 which returns different answers is the number 36.. but 36 is not a square root of any number of the list in test 4!!
Sagar Rupapara
on 4 Nov 2016
great solution
David Verrelli
on 19 Mar 2017
Agree with Mattias: the Test Suite is defective, and not consistent with the problem specification.
Having an input of [1] is OK, but result should be false, as there is no OTHER element to compare the 1 to!
ishmam zabir
on 26 Apr 2017
can you share the shortest code?
Marco Green
on 11 May 2018
easy
Ryan Klots
on 4 Dec 2018
Fun question!
asa czylabson
on 30 Jan 2019 at 20:59
the word "other" should be ignored in the description...
Solution Comments
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1 Comment
Natasa
on 1 Feb 2019 at 22:55
Wow! This took me a couple of days to solve, but I did it and I’m very proud! :D
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1 Comment
Myeongseon Choi
on 27 Jun 2018
Test case : a = [20:30] contains a square. but its expected error is false. It should be fixed
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1 Comment
Jafar Mortadha
on 14 Jan 2018
How is the output true if the vector contains only one number? People posting such meaningless solutions: Please have some common sense!
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1 Comment
Oliviero Allan Ceresa Genet
on 11 Nov 2017
easy easy
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1 Comment
Dustin Jones
on 12 Jul 2017
That's better...
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2 Comments
Dustin Jones
on 12 Jul 2017
a little smaller now
DilRavsh
on 20 Aug 2017
Nice ☺
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1 Comment
Dustin Jones
on 12 Jul 2017
Works
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1 Comment
Dustin Jones
on 12 Jul 2017
just kidding...
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1 Comment
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
very easy
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1 Comment
Noriko Hounoki
on 27 Dec 2016
I want to make this code shorter!!
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1 Comment
Noriko Hounoki
on 24 Dec 2016
Case2,a = [20:30],fails.
Others pass.
Why???
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1 Comment
Habeeb Ali
on 23 Dec 2016
in 2 test suite in a=[20:30] , contains 5^2 =25 so it has to be true not false
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1 Comment
Zhang Liang
on 25 Jul 2016
But there seems to be a better choice. Why forgetting ismember?
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2 Comments
Gary Ong
on 10 Jun 2016
Test 2 in the test suite is wrong!
25 is clearly a perfect square.
Matthew Stuckey
on 15 Jun 2016
the problem is to see if a number is the square of another number in the vector. Although 25 is a perfect square, 5 is not included in the vector
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1 Comment
Pankaj Soni
on 24 Apr 2016
function example(n)
clc
y = n;
for i = 1:1:length(y)
for j = 1:1:length(y)
while y(i) == sqrt(y(j))
fprintf('true\n');
return
end
while y(i) ~= sqrt(y)
fprintf('false\n');
return
end
end
end
% my code runs successfully in matlab
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2 Comments
Michael
on 28 Mar 2016
Though it passes the test suite, I feel like I could make this a better way but I am drawing a blank. Any feedback would be appreciated.
Seung Yub Lee
on 3 Dec 2016
good
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3 Comments
prakirt
on 24 Mar 2016
if a = [20:30] the output should be true as 25 is a perfect square, while in the test case output is given to be false.
Michael
on 29 Mar 2016
25 is not a square of any other members of the group. If the group included 5 it would be true.
Dan Po
on 24 Oct 2016
hur dur durrr durr. sqrt(25)==5, not included in givens
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1 Comment
Gouda
on 8 Sep 2015
Yeah, I did it
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2 Comments
Alexander Wickstrom
on 29 Jul 2015
My solution returns false for [20:30]; why not for [6 10 12 14 101]?
Sebastian
on 8 Sep 2015
Instead of a(1):a(end) you should just write a.
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2 Comments
Zhao Dennis
on 29 Mar 2015
Where did I do wrong？
Tim
on 31 Mar 2015
The desired results are not the character strings 'true' and 'false' but the logical values true and false.
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1 Comment
kunal
on 26 Aug 2014
hint ; any and ismember.
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1 Comment
Chandan singh
on 29 Jul 2014
submitted tested solution but still showing error......
L 17 (C 1-3): Parse error at END: usage might be invalid MATLAB syntax.
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2 Comments
Beshir Aman
on 25 Aug 2014
interesting solution... I like it :)
Sebastian
on 8 Sep 2015
I disagree. Almost every problem has a solution wrapped in this function. It's cheating as it hides the complexity of the code from the scoring algorithm. That's why "eval" is not allowed ...
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1 Comment
Kanchibhotla Chandra Sekhar
on 2 Aug 2013
This is the correctly executing in matlab
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1 Comment
Frequency Domain
on 24 Jul 2013
I wonder...if you cheat, why even bother to actually solve the problem?
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1 Comment
Jamie Sargant
on 4 Jun 2013
I have not heard of ismember before, thanks.
As primitive as my solutions are, I learn just as much from reading other peoples as doing the problem itself. Great setup mathworks :)
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1 Comment
Hardajit
on 25 Aug 2012
Code works on Matlab, but not on your test suite?
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1 Comment
Dishant Arora
on 13 Aug 2012
Srtr2func, classic way:)a new thing learned.
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2 Comments
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1 Comment
Charles Brent
on 3 Apr 2012
test case 3 should be 'false'
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1 Comment
Malte Schledjewski
on 5 Mar 2012
it states 'one of the other' numbers, so for a = [1] it should be false
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1 Comment
Ankur Verma
on 9 Feb 2012
Assertion 2. is not correct. vector 'a' return with 6th element as 25 & thts a perfect square.. So it must be true!!
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