Problem 2397. Leap Year

According to Gregorian Calender(which is in use now, in many countries),decide whether a given year is a leap year or not. Give 'true' if the given year is a leap year and 'false',if not.

Note: In the Gregorian calendar 3 criteria must be taken into account to identify leap years:

The year is evenly divisible by 4; If the year can be evenly divided by 100, it is NOT a leap year, unless; The year is also evenly divisible by 400. Then it is a leap year.

Solution Stats

47.33% Correct | 52.67% Incorrect
Last Solution submitted on Dec 15, 2024

Problem Comments

Solution Comments

Show comments

Problem Recent Solvers104

Suggested Problems

More from this Author1

Problem Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!