given the 1x5 vector x, y must be the square of the horizontal concatenation of the third and fifth elements. So, if x = [1 1 1 1 1], y must be [1 1].
The example you give in the problem statement is not very demonstrative.
HAHAHAHA Matt: this was great!!!
Sum of diagonal of a square matrix
Make a random, non-repeating vector.
Given a matrix, return the last eigen value
Try 1.5.4: Celsius to Fahrenheit
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