Another trick: if the last 4 digits of the number are divisible by 16, the full number is divisible by 16. So far as I know, if the last X digits of a number are divisible by 2^X, the entire number is divisible by 2^X.
@James: nice trick! (and I guess the proof arises from 10^x being always exactly divisible by 2^x, so "iff" also applies?)
perhaps less interesting but I guess you could do the same with powers of 5, iff the last X digits of a number are divisible by 5^x, then the entire number is divisible by 5^x...
Project Euler: Problem 7, Nth prime
Flag largest magnitude swings as they occur
Create matrix of replicated elements
Find vampire numbers
Compute Fibonacci Number
Divisible by 14
Stress-Strain Properties - 3
Not square-free number sequence
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