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Daniel Bending
Daniel Bending
Dernière activité le 31 Oct 2023

Hi All,
I'm currently attempting to implement a Hodgkin-Huxley-type model of membrane potential, ideally I would like a species that represents the membrane potential as its own distinct entity, so as the reference elsewhere. I've currently established a molarity-based work around but it would be great if I could set the units for the species as millivolt, but that throws an error.
Is there an established way to do this? I imagine I'm not the first person to be trying to model a voltage-gated ion channel!
Thank you for your help.
Image Analyst
Image Analyst
Dernière activité le 31 Oct 2023

Just in time for Halloween.
Share your fun photos in the comments!
Hello,
I've looked around and I haven't found anything obvious about this, but is it possible to link to species/reactions, graphically, in a non-mass transfer sense? I have areas in my model where it would conceptually make sense to be able to see that species or reactions are linked, but if I link them in the standard way it demands that it be involved in the stoichiometry.
Perhaps some kind of dotted line, or similar?
Thank you, best regards,
Dan
Julian
Julian
Dernière activité le 5 Fév 2024

I know the latest version of MATLAB R2023b has this feature already, put it should be added to R2023a as well because of its simplicity and convenience.
Basically, I want to make a bar graph that lets me name each column in a basic bar graph:
y=[100 99 100 200 200 300 500 800 1000];
x=["0-4" "5-17" "18-29" "30-39" "40-49" "50-64" "65-74" "75-84" "85+"];
bar(x,y)
However, in R2023a, this isn't a feature. I think it should be added because it helps to present data and ideas more clearly and professionally, which is the purpose of a graph to begin with.
Matt J
Matt J
Dernière activité le 1 Mar 2024

Would it be a good thing to have implicit expansion enabled for cat(), horzcat(), vertcat()? There are often situations where I would like to be able to do things like this:
x=[10;20;30;40];
y=[11;12;13;14];
z=cat(3, 0,1,2);
C=[x,y,z]
with the result,
C(:,:,1) =
10 11 0
20 12 0
30 13 0
40 14 0
C(:,:,2) =
10 11 1
20 12 1
30 13 1
40 14 1
C(:,:,3) =
10 11 2
20 12 2
30 13 2
40 14 2
Image Analyst
Image Analyst
Dernière activité le 10 Nov 2023

Wait for Walter, the rest of us are mere users.
Image Analyst
Image Analyst
Dernière activité le 16 Oct 2023

Image Analyst
Image Analyst
Dernière activité le 16 Oct 2023

Image Analyst
Image Analyst
Dernière activité le 16 Oct 2023

Image Analyst
Image Analyst
Dernière activité le 16 Oct 2023

Stand Back. I'm going to try MATLAB.
Image Analyst
Image Analyst
Dernière activité le 16 Oct 2023

Embarassed by Walter Roberson
Image Analyst
Image Analyst
Dernière activité le 16 Oct 2023

Image Analyst
Image Analyst
Dernière activité le 16 Oct 2023

Image Analyst
Image Analyst
Dernière activité le 16 Oct 2023

Image Analyst
Image Analyst
Dernière activité le 16 Oct 2023

Image Analyst
Image Analyst
Dernière activité le 16 Oct 2023

Image Analyst
Image Analyst
Dernière activité le 16 Oct 2023

MATLAB Road in theaters May 15, 2024.