The equation is of form, f(x) = 0. Provide the function, 'f' and provide two guesses. If the guesses are not according to bisection rule a message will be displayed on the screen.
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Thank you very much Brato! Its very useful code. Saves a lot of time : )
Justin: The way to use this code is as follows (the way I used it)
lets say we are required to find the value of x in equation x2 -2x =2
Lets say our initilal extreme guesses are 0 and 4
eqn= @(x) (x^2)-2*x-2;
I hope it helps!
For example, if my function is x^2, where do I define x?
Where do I enter the limits and the function?
Inspired: Bisection Method Root Finding
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