Bisection Method
version 1.0.0.0 (1.23 KB) by
Brato CHAKRABARTI
A very simple piece of code to solve a equation. But may come handy at times.
The equation is of form, f(x) = 0. Provide the function, 'f' and provide two guesses. If the guesses are not according to bisection rule a message will be displayed on the screen.
Please rate it if you find useful
Comments and Ratings (16)
MATLAB Release Compatibility
Created with
R2010a
Compatible with any release
Platform Compatibility
Windows macOS LinuxTags
Acknowledgements
Inspired: Bisection Method Root Finding
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Gyan Swarup Nag (view profile)
Erik Hoberg (view profile)
Hanan Ronaldo Quispe Condori (view profile)
Faisal Alessa (view profile)
muazam ali (view profile)
shivam gaur (view profile)
RJ Lluisma (view profile)
Yogesh Shamsunder Kumbargeri (view profile)
Thank you very much Brato! Its very useful code. Saves a lot of time : )
Justin: The way to use this code is as follows (the way I used it)
lets say we are required to find the value of x in equation x2 -2x =2
Lets say our initilal extreme guesses are 0 and 4
eqn= @(x) (x^2)-2*x-2;
answer= bisection(eqn,0,4);
I hope it helps!
Adam Massias (view profile)
Romina Mir (view profile)
Nuria Ortiz (view profile)
Jose Franco Abay-abay (view profile)
Michael Kusaba (view profile)
Justin Covington (view profile)
For example, if my function is x^2, where do I define x?
Justin Covington (view profile)
Where do I enter the limits and the function?
Yash (view profile)
very useful