Reshape Array after Padding/Truncating Mismatching Dimension

Use reshape function without worrying about dimension sizes, choose either to truncate your vector or pad it to match the desired dimensions

B = reshape0(A,sz,method,padWithWhat) reshapes A using the size vector, sz, to define size(B). For example, reshape(A,[2,3]) reshapes A into a 2-by-3 matrix. sz must contain at least 2 elements. if prod(sz) is not the same as numel(A), this function will either truncate or pad the input.

example
B = reshape0(A,[sz1,sz2,...,szN]) reshapes A into a sz1-by-...-by-szN array where sz1,...,szN indicates the size of each dimension. You can specify a single dimension size of -1 to have the dimension size automatically calculated, such that the number of elements in B matches the number of elements in A. For example, if A is a 10-by-10 matrix, then reshape0(A,[2,2,-1]) reshapes the 100 elements of A into a 2-by-2-by-25 array.
If prod(sz) is not the same as numel(A), this function with either truncate or pad (default) the input to match. For example is [A, padSize] = 1:21 (1x21 array), then B = reshape(A,[-1,5],'truncate') will truncate padSize elements and reshape the array into a 4x5 array. And B = reshape(A,[-1,5],'pad') will pad array with padSize elements and reshape the array into a 5x5 array.
You can define with what to pad the array, for example, if A = false(4,5), then [B,padSize] = reshape0(A,[-1,7],'pad',true) will pad A with true(padSize,1) and reshape the array into a 3x7 array.