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Mohamed Turkmani


Last seen: presque 2 ans il y a Actif depuis 2022

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Question


how to change decimal point place
hi, i have audio numbers that are printed as : 3.261505126953125 3.227813720703125 3.267242431640625 3.217407226562...

presque 2 ans il y a | 1 réponse | 0

1

réponse

Question


frequency shift slider in real time
i have the following code that reads an audio file, adds a frequency (the bold line) to the file and plots it , my question is t...

environ 2 ans il y a | 1 réponse | 0

1

réponse

Question


playing a nonstop audio file
how can i play an audio file without stopping kinda like a loop in app designer [y,Fs] = audioread(app.files); sound(y,Fs) th...

environ 2 ans il y a | 1 réponse | 0

1

réponse

Question


mixing audios according to array value
hi i have the following code which mixes two audios and plots them : Fs = 44100; [y,Fs] = audioread("sound and 1000 new.wav");...

environ 2 ans il y a | 1 réponse | 0

1

réponse

Question


increasing amplitude of sine wave
hi i want to create i simple sine tone that has increasing amplitude kinda like a fade in 3 seconds i wrote the following code...

environ 2 ans il y a | 2 réponses | 0

2

réponses

Question


Arrays have incompatible sizes for this operation.
i have the following code which mixes two audios as the user enters the number he wants to mix freq = str2double(get(handles.e...

environ 2 ans il y a | 1 réponse | 0

1

réponse

Question


changing audio frequency to a constant
lets say i have an audio that has so many different frequencies, can i modify its frequency to constant and run it at 2000 hz fo...

plus de 2 ans il y a | 1 réponse | 0

1

réponse

Question


changing frequency of an existing audio
hi i have wrote a simple code as the following. [y,fs] = audioread("Sound.wav"); sound(y,fs); i know that i can change ...

plus de 2 ans il y a | 1 réponse | 0

1

réponse

Question


getting x and y values and writing them
hi, i have created a user interface that gets sampling frequency and frequency from the user and plots it by the following code:...

plus de 2 ans il y a | 1 réponse | 0

1

réponse