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Sequential, row-wise reshape of an M–by–N matrix to form a 1–by–N vector
Dumb question. Let's say I have the following matrix: A = [2 1 4 3 6 5 8 7 10 9]; I...
plus de 4 ans il y a | 1 réponse | 0
1
réponseCompare Data from two tables and show how close the comparison is as a percentage
How are you loading in the data? If you're currently using readtable(), I strongly encourage you to instead use textscan(). In d...
plus de 4 ans il y a | 1
| A accepté
Removing zeros from a binary array if length of zeros is lesser than a value
k = [0;0;0;0;0;0;0;1;0;1;1;1;0;0;0;0;0;0;1;1;0;0;0;0]; y = regexp(num2str(k)', '(?<=[0]{5,})0*', 'split'); z = strjoin(cellfun...
presque 5 ans il y a | 0
My school needs to upgrade its license. I do not know what toolboxes to request. Who should I ask for advice?
Hi Valerie: I was at one point a lab technichian, and though I did not have the higher-level adminstrative role that you seem ...
presque 5 ans il y a | 0
| A accepté
Question
regexp: what am I missing from the documentation?
I have tried to carefully read the regexp documentation, and I am able to sucessfully implement regexp in the simplest cases. F...
presque 5 ans il y a | 1 réponse | 0
1
réponseConvert String array into Cell array
Yes, this also helped me. Thanks a lot.
environ 5 ans il y a | 0
Append a char vector to a subset of cells (whose indices are known) in cell array of character vectors
Alright, this was easily achieved with the following (continuing from the example given abvove): mynewcell = strcat('cal_'), m...
plus de 5 ans il y a | 0
Question
Append a char vector to a subset of cells (whose indices are known) in cell array of character vectors
Hello MATLAB community: I am trying to determine the most effective way of going about the following task. I have a cell array...
plus de 5 ans il y a | 2 réponses | 0
2
réponsesQuestion
Get range of integer values from adjacent column elements (integers) for multiple rows.
Note: (inadvertent early submission with question incomplete) Dear MATLAB Community: There is perhaps an even more elegant so...
environ 6 ans il y a | 1 réponse | 0