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I am facing problems in solving this question... I put my code .. please help
I am facing problems in solving this question .. I will put my code and please help me to correct my working Consider the fo...

plus de 4 ans il y a | 1 réponse | 0

1

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Question


help me to find the last required in this question please
I have this question ... I solved the first three required but I dont know what to do with the last one ( last required ) ple...

plus de 4 ans il y a | 3 réponses | 0

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Is my code for this question correct or not ?
Find and sketch the signal y(t) which is the convolution of the two pairs if signals. x = (exp(-2*t) - C*exp(-10*t)).*heavisi...

plus de 4 ans il y a | 1 réponse | 0

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my attempt to generate and plot some signals.. please tell me whats wrong here!
these are the signals: x1(t) = sin(10*pi*t ) , x2(t)=(1/3) sin(30*pi* t) , x3(t) = ( 1/5) sin(50* pi * t ) Gene...

plus de 4 ans il y a | 1 réponse | 0

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This is my attempt to generate and plot this signal .. which one of these is right? .. please help
This is my attempt to generate and plot this signal which one of these is right? .. please help x (t)=π[(t -3)/A ]+π[(t -...

plus de 4 ans il y a | 1 réponse | 0

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which one of these is the right sol.? and let me know my mistakes please ..
xb (t)= r(t ) - r(t-A ) - r(t-B ) + r(t-C ) A = 3, B = 4 and C = 4. which one of these is the right sol. and let me kn...

plus de 4 ans il y a | 2 réponses | 0

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Please check if my work is correct
Its my first time using matlab , so please tell me what I'm doing wrong here : A. x (t)=π[(t -3)/A ]+π[(t -C) /B] A = 3, B =...

plus de 4 ans il y a | 1 réponse | 0

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pleas, how can I solve this problem ? how can I plot these signals ?
Consider the following signals: x1(t) = sin(10*pi*t ) , x2(t)=(1/3) sin(30*pi* t) , x3(t) = ( 1/5) sin(50* pi * t...

plus de 4 ans il y a | 1 réponse | 0

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Question


How can I generate and plot these signals in matlab ?
A. x (t)=pi[(t -3)/A ]+pi[(t -C) /B] B. x (t)= r(t ) - r(t-A ) - r(t-B ) + r(t-C ) A = 3, B = 4 and C = 4.

plus de 4 ans il y a | 1 réponse | 0

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