photo

Mohiedin Bagheri


Last seen: environ 2 ans il y a |  Actif depuis 2021

Followers: 0   Following: 0

Statistiques

  • Thankful Level 2

Afficher les badges

Feeds

Afficher par

Question


how to display an output on a plot itself?
Hi friends, for this code: x = linspace(-5,2); y = -x-3; z = 2*x figure(1) plot(x, y) hold on plot(x, z) legend('x','y...

environ 2 ans il y a | 2 réponses | 1

2

réponses

Question


why fsolve cant find the solutoin?
Hello, I am trying to use fsolve to find intersection of two functions (intersection of two functions 'ia' and 'ic') . please ...

environ 2 ans il y a | 1 réponse | 0

1

réponse

Question


Solve a nonlinear function with one variable
Hi, I need to solve this function using Matlab in single script: x - x^2 + 2*{sin(x)*(x-1)} = 0 Would you be able to provide ...

environ 2 ans il y a | 2 réponses | 0

2

réponses

Question


How can I solve this problem in MATLAB? Warning!
Hi everybody, I am trying to solve a system of four equations with four unknown in matlab as below: F = 96485 syms a b c d e...

environ 3 ans il y a | 1 réponse | 0

1

réponse

Question


How to display answers for a system of two nonlinear equations, in scientific notation?
Hello all, I have solved this system of equations in matlab syms x y sol = solve([((2*x^2)/(3-y))+2==-50, y/(2*x-3)-3==4/7],...

environ 3 ans il y a | 1 réponse | 0

0

réponse

Question


What does 'li' mean?
Hello all, I have solved an equation in matlab using the following code: syms x ththa2 = (2*exp(5*x))/(3*exp(2*x)+1*exp(-2*x...

plus de 3 ans il y a | 3 réponses | 0

3

réponses

Question


Draw a tangent line with a given slope in Log scale
Dear all, I have a graph datapoints loaded in MATLAB. Y axis is Voltage (E) and x-axis is in Log scale. I have to draw a tangen...

plus de 3 ans il y a | 1 réponse | 0

1

réponse

Question


How can I write a matlab code to solve these equations in matlab?
Please see attached image. All K values are a function of potential. Potential values are given. I apprecuiate that if someone c...

plus de 3 ans il y a | 1 réponse | 0

1

réponse