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Tony Stianchie


Last seen: environ un an il y a Actif depuis 2022

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Modifying A Variable in an ODEFUN/Boundary Value Problem
I am trying to modify with each step across my odefun the values of k, mu, and c. I'd like for these variables for change with ...

environ un an il y a | 1 réponse | 0

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Finite Differencing Transient Conduction
Hello, I'm attempting to conduct a finite difference approach to a transient conduction problem. Rows are time steps Column...

environ un an il y a | 2 réponses | 0

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Question


Solving a PDE using PDE Toolbox
This problem invoves an inner pipe with a constant wall temp, an annular space with conduction only, and an insulated outer pipe...

environ un an il y a | 1 réponse | 0

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réponse

Question


Plotting from For Loop ODEFUN and BVP4C Initial Guess
%% Thetadot(0) vs Pr m = 0; Prinf = 1000; for Pr = linspace(0,Prinf,1) solinit = bvpinit(Pr,[0 0 0 0 0.05]); sol = b...

environ un an il y a | 1 réponse | 0

1

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Summing a series within a For Loop
H = 0.1; I = 5; Y = 0; BI = zeros(I,1); for i = 1:I b = fzero(@(b)(b*tan(b)-H),pi*i); BI(i) = b ;...

plus d'un an il y a | 1 réponse | 0

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Finding the roots across a range of values
I'd like to find the roots of b for the array b(i,1) and store those values in BI(i) H = 0.1; I = 200; Y = 0; b...

plus d'un an il y a | 1 réponse | 0

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Question


For Loop Starting at Zero
I'd like to run my Theta for loop across the length of X ( 0 to 1) with my stored values of BI H = 0.1; I = 200; Y = 0; BI...

plus d'un an il y a | 1 réponse | 0

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Question


Solving for Zeros Across a Range
I'd like to solve and store the valves for which bi = 0 across a range i=I H = 0.1; I = 200; bi = zeros(I,1); for i = l...

plus d'un an il y a | 1 réponse | 0

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Question


Using a function and fsolve with a for loop
I'd like to solve the system of 4 non linear equations and 4 unknonws over a span of values for T. I'm recieving the follo...

plus d'un an il y a | 2 réponses | 0

2

réponses

Question


Loop with Different Step Criteria
Hi - I am trying to step through a loop taht goes: on K=1 (first step), my conditions are known (temperature, T and enthalpy, h...

plus de 2 ans il y a | 1 réponse | 0

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