Shivangi Chauhan

Last seen: plus de 3 ans il y a | Actif depuis 2016

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LImit is not corrcet
Hi All, I am trying to find the limit of below function in matlab : limit(( -24*sin(x)+6*x*exp(x)+30*x*sin(x)+6*x*cos(x)-exp...

presque 8 ans il y a | 1 réponse | 0

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How can we do calculation in Matlab?if X(i)=Y(i)+2*Z(i-1)-3*T(i+1);Then how can calculate 15*X(i+1)+12*X(i)-3*X(i-1) using the value of X(i).
How can we do calculation in Matlab? if X(i)=Y(i)+2*Z(i-1)-3*T(i+1); Then how can calculate 15*X(i+1)+12*X(i)-3*X...

plus de 8 ans il y a | 1 réponse | 0

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Hi, I am trying this in m file but there is an error occurring as "Incomplete or misformed expression or statement." where is the problem? X=[-1 -0.4423 -0.3 -0.4000 -0.3258 -0.3636 -0.3418]; for i= 1:3 N(i+2) = (7.8)*(X(i)+ 3*(X(i+1)+6*X(i+2)+1
Hi, I am trying this in m file but there is an error occurring as "Incomplete or misformed expression or statement." where is t...

plus de 8 ans il y a | 1 réponse | 0

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If A is 4 banded 14 X 14 matrix and B= 14 X 1 matrix. Then how can i solve the system of equation for X where AX=B. A= 1 -2 1 8 -8 3 1 8 -8 3 1 8 -8 3 . .. ... ....... 1 8 -8 3 1 7 1
If A is 4 banded 14 X 14 matrix and B= 14 X 1 matrix. Then how can i solve the system of equation for X where AX=B. N=16

plus de 8 ans il y a | 1 réponse | 0

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Hello all,I am trying to solve this in command window f = @(X)((x.^3)-2*(x.^2)-5*(x-3))*exp(x); Xn = (1:15)/16; fXn = f(Xn) And i am getting following error: Error using ==> mpower Matrix must be square.
Hello all,I am trying to solve this in command window f = @(X)((x.^3)-2*(x.^2)-5*(x-3))*exp(x); Xn = (1:15)/16; fXn =...

plus de 8 ans il y a | 1 réponse | 0

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Question

Is matlab not considering L Hospital's rule, while calculating limits? Becoz there r two different answers of the function f=(1 - (cos(x)))/((2* ((x^3)))* sin(x)).
Is matlab not considering L Hospital's rule, while calculating limits? Becoz there r two different answers of the function f=(1 ...

presque 9 ans il y a | 1 réponse | 0

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How can we find function value f1, f2,.......f15? If function is defined by fi = Xi +3*Xi+1 - 4Xi+2 + Xi+3 and Xi=[2 5 -6 8 9 45 4 4 4 4 8 9 4 1 5]; i=1,2,......15.
How can we find function value f1, f2,.......f15? If function is defined by fi = Xi +3*Xi+1 - 4Xi+2 + Xi+3 and Xi=[2 5 -6 8 ...

presque 9 ans il y a | 1 réponse | 0

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While solving a system of linear equations, i am getting answer in decimal. How can find answer in rational no.? I know it's easy, but i am not able to find.
While solving a system of linear equations, i am getting answer in decimal. How can find answer in rational no.? I know it's eas...

presque 9 ans il y a | 1 réponse | 0

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Can any one help to find the limit of a function f=(2-2*cos(x))/x^3*sin(x)-cos(x)/x*sin(x) where x tending 0. correct ans is -5/12 but im getting zero.
Can any one help me to find the limit of a function f=(2-2*cos(x))/x^3*sin(x)-cos(x)/x*sin(x) where x tending 0. correct ans is ...

presque 9 ans il y a | 1 réponse | 0

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Can any one help to find the limit of a function f=(2-2*cos(x))/x^3*sin(x)-cos(x)/x*sin(x) where x tending 0. correct ans is -5/12 but im getting zero.
Can any one help me to find the limit of a function f=(2-2*cos(x))/x^3*sin(x)-cos(x)/x*sin(x) where x tending 0. correct ans is ...

presque 9 ans il y a | 1 réponse | 0

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when i apply limit(x^3-6*(x-sin(x)))/(6*(x^4)*sin(x)), i am getting: ans = 0; but correct ans. is 1/120; Am i doing something wrong?can i replace x by theta?
when i apply limit(x^3-6*(x-sin(x)))/(6*(x^4)*sin(x)) i am getting: ans = 0; but correct ans. is 1/120; Am i doing s...

presque 9 ans il y a | 1 réponse | 0

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How do i find the function value for different values of xi &Yi; where f=function(x,y);i=1,2,..............n (n may be 15, 50 or 100)
How do i find the function value for different values of xi & Yi; where f= function(x,y); i=1,2,..............n (n may be 15, 50...

presque 9 ans il y a | 1 réponse | 0

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Question

How do i create a (n x n) matrix using algorithm or other way whose elements are either -1, +3, –3 & 1 , otherwise 0, such that a11=a22=a33=.....=-1, a12=a23=a34=.....= 3, a13=a24=a35=.......= -3, a14=a25=a36=....= 1,.
How do i create a (n x n) matrix using algorithm or other way, whose elements are either -1, +3, –3 & 1 ,such that a11=a22=a33=...

presque 9 ans il y a | 1 réponse | 0

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