Effacer les filtres
Effacer les filtres

put me out of my misery

3 vues (au cours des 30 derniers jours)
Rizwana
Rizwana le 31 Jan 2014
i have 3 matrices..
x = 1 * 264;
y = 1* 264;
z = 1 * 264;
contour(x,y,z) % error z must be 2* 2 or more
hence i did
[X,Y] = meshgrid(x,y); Z =griddata(x,y,z,X,Y);
contour(X,Y,Z) is giving some weird plot. Not desirable.
Now how to do it...
  2 commentaires
Iain
Iain le 31 Jan 2014
What are you trying to plot?
contour(x,y,z) is expecting x to be a vector with n elements, y a vector with m elements, and z to be n by m (or is it m by n)
Rizwana
Rizwana le 31 Jan 2014
Modifié(e) : Rizwana le 31 Jan 2014
my x is a 1 col,264 row matrix reading radius,y is 1 col,264 row matrix reading angles in degrees. and z is pressure gain 1* 264. I want to plot radius versus circumferential angle in degrees with contours of pressure. Thank you

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Réponse acceptée

Bjorn Gustavsson
Bjorn Gustavsson le 31 Jan 2014
Modifié(e) : Bjorn Gustavsson le 31 Jan 2014
First you have to get yourself a good overview of what you actually have, I suggest using scatter:
qwe = xlsread('yourfile.xls');
scatter(qwe(:,1).*cos(qwe(:,2)*pi/180),...
qwe(:,1).*sin(qwe(:,2)*pi/180),15,...
(qwe(:,3)-min(qwe(:,3)))*5+5,'filled')
So there you see some odd spots (sensor faulty or something?). At least easy to reinterpolate outside that region:
X = 24.7:0.1:27;
Y = 0:0.1:5;
[X,Y] = meshgrid(X,Y);
Z = griddata(qwe(:,1).*cos(qwe(:,2)*pi/180),...
qwe(:,1).*sin(qwe(:,2)*pi/180),qwe(:,3),X,Y);
% Or any of the newer variants like Walter suggested.
% do the contour:
hold on
contour(X,Y,Z,1.25:0.025:max(qwe(:,3)),'b')
HTH
  2 commentaires
Rizwana
Rizwana le 3 Fév 2014
Modifié(e) : Rizwana le 3 Fév 2014
Than you for your help. Iam great full to you for teaching me so many things in simple 5 lines of codes:). Just one doubt... You have done radius* cos(theta) for qwe(:,1).*cos(qwe(:,2)*pi/180) and radius * sin(theta) for qwe(:,1).*sin(qwe(:,2)*pi/180)... While plotting do we should convert degrees into radian??? because you have multiplied it with pi/180?? Is it compulsory???
Bjorn Gustavsson
Bjorn Gustavsson le 3 Fév 2014
Yes, the trigonometric functions work on radians. You'd be better off learning to use radians.

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Plus de réponses (3)

Mischa Kim
Mischa Kim le 31 Jan 2014
Rizwana, first option works just fine. Make sure that Z is an mxn matrix, where m and n are the length of the two vectors x and y. meshgrid , e.g., generates an appropriate grid.
x = rand(10,1);
y = rand(10,1);
[X,Y] = meshgrid(x,y);
Z = sin(X)+cos(X+Y);
figure
contour(X,Y,Z)
or see the documentation.
  3 commentaires
Mischa Kim
Mischa Kim le 31 Jan 2014
The contour plot is more of a 3D type plot, where the dependent variable (Z) depends on two variables (X, Y). So it is not quite clear to me what you would like to achieve.
Rizwana
Rizwana le 31 Jan 2014
I will attach an excel file. 1st row is radius, 2nd row is circumferential angle in degrees and z is 3rd row whose contours i need to plot... This is just experimental data collected... are you trying to get idea of what iam trying to plot???

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Iain
Iain le 31 Jan 2014
Modifié(e) : Iain le 31 Jan 2014
Looks like you actually want: plotyy or subplots:
plotyy(x,y,x,z) % plot angle against radius on the left hand y axis, and pressure against radius on the right hand y axis.
subplot(211)
plot(x,y)
subplot(212)
plot(x,z)
or
subplot(121)
plot(x,y)
subplot(122)
plot(x,z)
obviously, switch the x,y,z's around to plot against what you want to. - contour plots are only valid for 2-D signals, and you've only got 3 1D signals.
  3 commentaires
Iain
Iain le 31 Jan 2014
Is circumferential pressure supposed to be a function of angle and radius?
If radius has "n" elements, and you have "m" angles, then you should get "n x m" pressures, and not have all three as being vectors.
For example, with a trivial function I know is wrong:
x= 0:0.1:1;
y= 0:36:360;
z = x' * y;
contour(x,y,z)
would work.
Rizwana
Rizwana le 31 Jan 2014
Its total pressure coefficient(z). In a turbine blade, pressure varies with radius and pitch variation... z is just set of data. Not a function.

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Walter Roberson
Walter Roberson le 31 Jan 2014
  7 commentaires
Walter Roberson
Walter Roberson le 31 Jan 2014
It appears that TriScatteredInterp appeared in R2009a. griddata() does exist in your release though.
Rizwana
Rizwana le 3 Fév 2014
Thank you. I will try downloading new 2013 version. Thank you very much for highlighting the other 2 functions i can use.

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