Plots for second order control system in the same graph

6 vues (au cours des 30 derniers jours)
Carlos
Carlos le 25 Mar 2014
Modifié(e) : Paul le 30 Mar 2014
I'm been trying to graph this equation without success.I keep getting an error message that says:Warning: Imaginary parts of complex X and/or Y arguments ignored.
Note: input is in radiant.
Here is my code:
% Exersice 11
x = input('Please enter vector x in degree: ');
z = [0.1 0.2 0.4 0.7 0.9];
y1 = 1-1/sqrt(1-z(1,1).^2).*exp(-z(1,1).*x).*sin(sqrt(1-z(1,1).^2)).*x+acos(x);
y2 = 1-1/sqrt(1-z(1,2).^2).*exp(-z(1,2).*x).*sin(sqrt(1-z(1,2).^2)).*x+acos(x);
y3 = 1-1/sqrt(1-z(1,3).^2).*exp(-z(1,3).*x).*sin(sqrt(1-z(1,3).^2)).*x+acos(x);
y4 = 1-1/sqrt(1-z(1,4).^2).*exp(-z(1,4).*x).*sin(sqrt(1-z(1,4).^2)).*x+acos(x);
y5 = 1-1/sqrt(1-z(1,5).^2).*exp(-z(1,5).*x).*sin(sqrt(1-z(1,5).^2)).*x+acos(x);
plot(x,y1,x,y2,x,y3,x,y4,x,y5, 'm'), xlabel('x in radiands'), ylabel('y(x)') ,title('1-1/{\surd}(1-\zeta^2)e^-^\zeta^xsin{\surd}(1-\zeta^2)x+cos^-^1(x)'), grid, legend('\zeta = 0.1','\zeta = 0.2','\zeta = 0.4','\zeta = 0.7','\zeta = 0.9')
  2 commentaires
Azzi Abdelmalek
Azzi Abdelmalek le 25 Mar 2014
What is the problem?
Carlos
Carlos le 25 Mar 2014
I should get a sinusoidal graph for each zeta plugged in and what I'm getting is a strange line.
See attached screenshots
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Réponse acceptée

Paul
Paul le 30 Mar 2014
Modifié(e) : Paul le 30 Mar 2014
Two things are wrong. One is the parenthesis before .x which should be on the end. The second is the acos(x) which should be acos(z(...)). Also it doesnt make sense that you ask x in degrees while it should be radians:
x = input('Please enter vector x in radians: ');
z = [0.1 0.2 0.4 0.7 0.9];
y1 = 1-(1/sqrt(1-z(1,1).^2)).*exp(-z(1,1).*x).*sin(sqrt(1-z(1,1).^2).*x+acos(z(1,1)));
y2 = 1-1/sqrt(1-z(1,2).^2).*exp(-z(1,2).*x).*sin(sqrt(1-z(1,2).^2).*x+acos(z(1,2)));
y3 = 1-1/sqrt(1-z(1,3).^2).*exp(-z(1,3).*x).*sin(sqrt(1-z(1,3).^2).*x+acos(z(1,3)));
y4 = 1-1/sqrt(1-z(1,4).^2).*exp(-z(1,4).*x).*sin(sqrt(1-z(1,4).^2).*x+acos(z(1,4)));
y5 = 1-1/sqrt(1-z(1,5).^2).*exp(-z(1,5).*x).*sin(sqrt(1-z(1,5).^2).*x+acos(z(1,5)));
figure;
plot(x,y1,x,y2,x,y3,x,y4,x,y5, 'm'), xlabel('x in radiands'), ylabel('y(x)') ,title('1-1/{\surd}(1-\zeta^2)e^-^\zeta^xsin{\surd}(1-\zeta^2)x+cos^-^1(x)'), grid, legend('\zeta = 0.1','\zeta = 0.2','\zeta = 0.4','\zeta = 0.7','\zeta = 0.9')
It would also be easier to just use z(2) instead of z(1,2) etc. and using a for loop like Mischa suggested would save you the copy paste code.

Plus de réponses (1)

Mischa Kim
Mischa Kim le 26 Mar 2014
Modifié(e) : Mischa Kim le 26 Mar 2014
Carlos, check out
function myDE()
prompt = {'xmin:','xmax:'};
name = 'Input x-range';
numlines = 1;
xlimits = inputdlg(prompt,name,numlines);
N = 100;
x = linspace(str2num(xlimits{1}),str2num(xlimits{2}),N);
z = [0.1 0.2 0.4 0.7 0.9];
hold all
for ii = 1:numel(z)
y = 1 - (1/sqrt(1-z(ii)^2))*exp(-z(ii)*x).*sin(sqrt(1-z(ii)^2)*x...
+ acos(z(ii)));
plot(x,y)
end
end
  1 commentaire
Carlos
Carlos le 29 Mar 2014
This is beyond my course scope. Could you simplify using more or less what I have above?
Thanks.

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