how to create diferential equation with initial conditions ?
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For the differential equation how would I create a Matlab function that takes no inputs and returns the following outputs:
- Two vectors, x and y, containing the points where the differential equation has been approximated and the corresponding value of the solution.
- A real number representing the integral of the approximated solution in the interval where the differential equation has been solved.
For the ordinary differential equation:
d3y dx3 + dydx - xy + d2ydx2 = 2;
x 3 [1:1; 5:8]
with initial conditions y(0) = 0:0616;dydx(0) = 0.5886; d2ydx2(0)=0.0989
2 commentaires
Star Strider
le 3 Avr 2014
Modifié(e) : Star Strider
le 3 Avr 2014
What does ‘x 3 [1:1; 5:8]’ mean?
RahulTandon
le 8 Juil 2015
x 3 [1:1, 5:8] means x3 = [1:1,5:8] Am i right?
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