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Effacer les filtres

select the row that contains the minimum of a column

3 vues (au cours des 30 derniers jours)
dolving
dolving le 27 Juin 2014
I have this matrix:
results =
0.0260 0.1040 0.0030 0.0246 0.0264 4.8818
0.0430 0.1040 0.0030 0.0194 0.0238 5.0857
0.0600 0.1040 0.0030 0.0164 0.0223 5.2897
0.0260 0.0870 0.0030 0.0245 0.0263 5.0856
0.0430 0.0870 0.0030 0.0194 0.0237 5.2896
0.0600 0.0870 0.0030 0.0167 0.0221 5.4936
0.0260 0.0700 0.0030 0.0246 0.0259 5.2896
0.0430 0.0700 0.0030 0.0194 0.0233 5.4937
0.0600 0.0700 0.0030 0.0164 0.0217 5.6976
0.0260 0.1040 0.0065 0.0331 0.0413 0
0.0430 0.1040 0.0065 0.0269 0.0322 4.0227
0.0600 0.1040 0.0065 0.0207 0.0264 4.4647
0.0260 0.0870 0.0065 0.0330 0.0409 0
0.0430 0.0870 0.0065 0.0268 0.0319 4.4648
0.0600 0.0870 0.0065 0.0208 0.0261 4.9067
0.0260 0.0700 0.0065 0.0330 0.0397 4.4648
0.0430 0.0700 0.0065 0.0269 0.0306 4.9067
0.0600 0.0700 0.0065 0.0208 0.0249 5.3487
0.0260 0.1040 0.0100 NaN 0 0
0.0430 0.1040 0.0100 0.0578 0.0639 0
0.0600 0.1040 0.0100 0.0445 0.0423 0
0.0260 0.0870 0.0100 NaN 0 0
0.0430 0.0870 0.0100 0.0577 0.0628 0
0.0600 0.0870 0.0100 0.0446 0.0411 0
0.0260 0.0700 0.0100 NaN 0 0
0.0430 0.0700 0.0100 0.0576 0.0584 0
0.0600 0.0700 0.0100 0.0445 0.0367 4.8460
I want to select the row that contains the minimum nonzero value of the last column.
I tried:
[minVal rowInd]=min(nonzeros(results(:,6)))
minVal =
4.0227e+003
row_idx =
10
This does give the value i want, but not the right row (it must be row_idx=11).
Any ideas would be welcome!!

Réponse acceptée

Guilherme Coco Beltramini
Guilherme Coco Beltramini le 27 Juin 2014
Use an auxiliary variable:
tmp = results(:,6); tmp(tmp==0) = NaN;
[minVal rowInd]=min(tmp)

Plus de réponses (1)

Star Strider
Star Strider le 27 Juin 2014
Test for the minimum first, then use find:
min6 = min(results((results(:,6) > 0),6));
ridx = find(results(:,6) == min6);

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