How I can integrate function if I have two variables?

Hi:
I am using trapz to integrate my function, but in my function I have two variables, what should I do if I want to integrate only one variable and keep the other one? if anyone can help me, I will be appreciate it.
Thank you
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1 commentaire

Laurence Lurio
Laurence Lurio le 2 Fév 2017
Modifié(e) : Laurence Lurio le 2 Fév 2017
Suppose you have f(x,y) and you want to integrate from A to B over x with y=y0. Then
y=y0
fun2=@(x)fun(x,y0)
result=integral(fun2,A,B)

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 Réponse acceptée

If you have already evaluated your function and have a matrix of (x,y) values for it, you can use trapz to integrate it in the dimension you want.
Example:
f = @(x,y) 3*x.^2 + 5*y.^3;
x = 0:0.1:5;
y = 0:0.1:7;
[X, Y] = meshgrid(x,y);
fmtx = f(X,Y);
fxint = trapz(x,fmtx,2);
figure(1)
surfc(X,Y,fmtx)
grid on
xlabel('X')
ylabel('Y')
Otherwise, you need to do the integration with the Symbolic Math Toolbox:
syms x y
f(x,y) = 3*x.^2 + 5*y.^3;
fint = int(f, x)

6 commentaires

ok, thank you for your answer. I tried with traps, because I want to express all the function with y(one of the variable) after integrating, I don't have any value for y, after integrating I need to solve a matrix equation to find y. So do you think traps is working for me? if I use int, after integrating, it is in the syms form, how can I solve that one?
My pleasure!
However, I do not understand your function, your data, or what you want to do. You can use matlabFunction (Symbolic Math Toolbox) to create an anonymous function (or function file) from your partially-integrated function as a function of the remaining variable.
Thank you, I will try like this.
My pleasure!
I was using "integral" function which didnt work, when I switched to this "int" function, it started working. Thanks!
My pleasure!
The trapz function integrates vectors and matrices numerically.
The integral function integrates functions numerically.
The int function integrates symbolic expressions and functions, and vpaintegral integrates them numerically.

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