Effacer les filtres
Effacer les filtres

How to plot the surface of multiple data sets ?

12 vues (au cours des 30 derniers jours)
Jean Volkmar
Jean Volkmar le 20 Août 2021
Commenté : Star Strider le 20 Août 2021
I have three different data sets each being constant in the z/l axis and want to plot the surface of them. I got the 3d plot working using plot3() :
All three lines have the same amount of data points so it should not be that hard to connect each point of each line with a straight line.
Here's the code for the figure:
figure(35);
set(gcf,'position',[x0,y0,width,height])
plot3(porous_upper(pathnumber_10,1).values(:,xc_x)*scale_x,porous_upper(pathnumber_10,1).values(:,xc_x+2)*scale_z,porous_upper(pathnumber_10,1).values(:,yc_x),"DisplayName","Porous Upper 1 p -10");
hold on;
plot3(porous_upper(pathnumber_10,2).values(:,xc_x)*scale_x,porous_upper(pathnumber_10,2).values(:,xc_x+2)*scale_z,porous_upper(pathnumber_10,2).values(:,yc_x),"DisplayName","Porous Upper 2 p -10");
hold on;
plot3(porous_upper(pathnumber_10,3).values(:,xc_x)*scale_x,porous_upper(pathnumber_10,3).values(:,xc_x+2)*scale_z,porous_upper(pathnumber_10,3).values(:,yc_x),"DisplayName","Porous Upper 3 p -10");
title(["Pressure p above porous layer";"Sidecoefficent Test -10"],'interpreter','latex',"FontSize",20)
set(gca, 'YDir','reverse')
xlabel('X/L', 'Interpreter','latex',"FontSize",16);
ylabel('Z/L', 'Interpreter','latex',"FontSize",20);
zlabel('$p$', 'Interpreter','latex',"FontSize",20);
legend("show","Location","Best","AutoUpdate", "off");

Réponse acceptée

Star Strider
Star Strider le 20 Août 2021
It would help to have the actual data.
N = 20;
X = (0:N-1);
Y = [1:3].'+zeros(size(X));
porous_upper = rand(20,3)+[0:2];
figure
plot3(X, Y(1,:), porous_upper(:,1))
hold on
plot3(X, Y(2,:), porous_upper(:,2))
plot3(X, Y(3,:), porous_upper(:,3))
hold off
grid on
figure
surf(porous_upper.')
Make appropriate changes to work with your data.
.
  6 commentaires
Jean Volkmar
Jean Volkmar le 20 Août 2021
Alright thanks alot ! :)
Star Strider
Star Strider le 20 Août 2021
As always, my pleasure!
.

Connectez-vous pour commenter.

Plus de réponses (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by