how I can make the matrix?

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Akash Pal
Akash Pal le 26 Août 2021
  1 commentaire
Star Strider
Star Strider le 26 Août 2021
I see no consistent relationship that could be coded as any sort of ‘rule’ as to what rows of 'A’ become ‘B’.
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the cyclist
the cyclist le 26 Août 2021
I think this does what you want. (It produces the correct output for your example.)
If not, I hope you can understand and adjust the logic.
A = [2 10 ;
2.5 8.9;
2.5 9 ;
2.65 9 ;
3 7 ;
3 8 ;
4 7.5;
4.5 4.9];
B = A;
idx = 2;
while idx < size(B,1)
if B(idx,1) >= B(idx-1,1) && B(idx-1,2) > B(idx,2)
idx = idx+1;
else
B(idx,:) = [];
end
end
B
B = 4×2
2.0000 10.0000 2.5000 8.9000 3.0000 7.0000 4.5000 4.9000

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