Need help to create a loop
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
In the code below, I am finding the value of Q for all values of k. Instead of finding value of Q one by one, is there a more efficient way of doing it using a loop?
e=2.7183;
gamma=0.1333;
k = [1,9,23,7,23,9,20,29,63,102,73,59,27,130,75,185,70,92,326]
Rt=0:0.01:10;
P = zeros(length(k)-1,length(Rt));
for i = 1:length(k)-1
lambda = k(i)*exp(gamma*(Rt-1));
P(i,:) = ((lambda.^k(i+1)).*exp(-lambda))/factorial(k(i+1));
P(i,:) = P(i,:) / sum(P(i,:));
end
Q2 = P(1,:).*P(2,:)
Q2 = Q2 /sum(Q2)
Q3 = P(1,:).*P(2,:).*P(3,:)
Q3 = Q3 /sum(Q3)
Q4 = P(1,:).*P(2,:).*P(3,:).*P(4,:)
Q4 = Q4 /sum(Q4)
Q5 = P(1,:).*P(2,:).*P(3,:).*P(4,:).*P(5,:)
Q5 = Q5 /sum(Q5)
plot(Rt,Q2,Rt,Q3,Rt,Q4,Rt,Q5)
0 commentaires
Réponses (1)
Alan Stevens
le 2 Oct 2021
How about:
e=2.7183;
gamma=0.1333;
k = [1,9,23,7,23,9,20,29,63,102,73,59,27,130,75,185,70,92,326];
Rt=0:0.01:10;
P = zeros(length(k)-1,length(Rt));
for i = 1:length(k)-1
lambda = k(i)*exp(gamma*(Rt-1));
P(i,:) = ((lambda.^k(i+1)).*exp(-lambda))/factorial(k(i+1));
P(i,:) = P(i,:) / sum(P(i,:));
if i==1
Q(i,:) = P(i,:);
end
if i>1
Q(i,:) = Q(i-1,:).*P(i,:);
end
end
for i = 2:5
Q(i,:) = Q(i,:)/sum(Q(i,:));
end
figure
plot(Rt,Q(2,:),Rt,Q(3,:),Rt,Q(4,:),Rt,Q(5,:))
Voir également
Catégories
En savoir plus sur Uncertainty Analysis dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!