Replacing sym with function handle
Afficher commentaires plus anciens
I gave my script below. In order to get my result i used 'sym' function.
But i want to implement without symbolic math toolbox, how to implement the same script with function handles?
syms phi
w = 2;
Nr = 20;
nr = sym(zeros(1, Nr));
wr = sym(zeros(1, Nr));
for n = 1:Nr
for i = 1:w
Awr = 50*(cos(i*2)-cos(i*9));
nr(1, n) = nr(1, n)+Awr*cos(i*(phi+2*n));
end
wr(1, n) = nr(1, n);
end
NR = vpa(nr+(56*3/2), 4)
WR = vpa(wr, 4)
Réponses (1)
Do you mean something like this?
phi = pi/3;
[nr, wr] = fn(phi);
disp(phi)
disp(nr(4)+56*3/2)
disp(wr(4))
function [nr, wr] = fn(phi)
w = 2;
Nr = 20;
nr = zeros(1, Nr);
wr = zeros(1, Nr);
for n = 1:Nr
for i = 1:w
Awr = 50*(cos(i*2)-cos(i*9));
nr(1, n) = nr(1, n)+Awr*cos(i*(phi+2*n));
end
wr(1, n) = nr(1, n);
end
end
4 commentaires
Bathala Teja
le 5 Oct 2021
Alan Stevens
le 5 Oct 2021
Your question specified not using the symbolic toolbox!
I chose a single value of phi as an example. You can pass as many values of phi as you like to the function, by using a loop.
Bathala Teja
le 5 Oct 2021
Alan Stevens
le 5 Oct 2021
You can use trapz. For example:
philo = 0;
phihi = pi;
phi = linspace(philo, phihi, 100);
dphi = (phihi-philo)/99;
nr = zeros(numel(phi),20);
wr = zeros(numel(phi),20);
Integral_nr = zeros(1,20);
Integral_wr = zeros(1,20);
for m = 1:numel(phi)
[nr(m,:), wr(m,:)] = fn(phi(m));
end
for k = 1:20
Integral_nr(k) = trapz(nr(:,k))*dphi;
end
plot(1:20,Integral_nr,'--o'),grid
xlabel('1:Nr'), ylabel('Integrals of nr')
function [nr, wr] = fn(phi)
w = 2;
Nr = 20;
nr = zeros(1, Nr);
wr = zeros(1, Nr);
for n = 1:Nr
for i = 1:w
Awr = 50*(cos(i*2)-cos(i*9));
nr(1, n) = nr(1, n)+Awr*cos(i*(phi+2*n));
end
wr(1, n) = nr(1, n);
end
end
Catégories
En savoir plus sur Calculus dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!

