Area under curve (no function)

36 vues (au cours des 30 derniers jours)
Rick
Rick le 9 Sep 2014
Commenté : Star Strider le 16 Jan 2021
Hello,
If I have a set of data such as
X = [0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.85];
rA = [-.0053, -.0052, -.0050, -.0045, -.0040, -.0033, -.0025, -.0018, -.00125, -.0010];
plot(X,-1./rA)
and I want to know the area under the curve generated in the graph, how would I do that? There is no function involved here, this is just raw data, so I know I can't use quad or any of those integral functions.
Thanks
  3 commentaires
Samarth Patil
Samarth Patil le 7 Juin 2018
how to find the area in an interval for such a plot?
Krishnendu Mukherjee
Krishnendu Mukherjee le 12 Sep 2018
Thanks a lot. It helped a lot.

Connectez-vous pour commenter.

Réponse acceptée

Star Strider
Star Strider le 9 Sep 2014
Modifié(e) : Star Strider le 9 Sep 2014
Use trapz. It’s designed to do exactly what you want.
Int = trapz(X, -1./rA)
produces:
Int =
306.7455
  5 commentaires
Saurabh Parmar
Saurabh Parmar le 25 Mai 2020
Thank You So Much! That helped a lot.
Star Strider
Star Strider le 16 Jan 2021
Everyone — My pleasure!

Connectez-vous pour commenter.

Plus de réponses (1)

Ashok
Ashok le 9 Juil 2016
% Find the number of pixels of the connected component
Bin_image - logical binary image CC = bwconncomp(Bin_image); CC numPixels = cellfun(@numel,CC.PixelIdxList); disp(numPixels);
% Find the number of pixels of the connected component
[Label,~]=bwlabel((Bin_image),8); [Label,~]=bwlabel(Bin_log_4mult,8); num=1; [row, ~] = find(Label==num); Obj_area=numel(row); display(Obj_area);

Catégories

En savoir plus sur Numerical Integration and Differentiation dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by