[m n] = size(image);
I tried this command earlier and it worked well but now showing this:
"Indexing cannot yield multiple results."

 Réponse acceptée

Star Strider
Star Strider le 24 Sep 2014

0 votes

Did you name one of your variables ‘size’ later in your code?

3 commentaires

VIJENDRA
VIJENDRA le 24 Sep 2014
yes.. i clear that variable and the function works normally... Thanks for your reply
Star Strider
Star Strider le 24 Sep 2014
My pleasure!
Image Analyst
Image Analyst le 24 Sep 2014
It's also not a good idea to take the size of a built in function like image ()! Hopefully your image is not really named that!
And actually, even if it has a different name, that way of calling size() can be risky. Why? Read Steve's blog: http://blogs.mathworks.com/steve/2011/03/22/too-much-information-about-the-size-function/. Better, if you know it's not a multispectral image but is a regular indexed, RGB, or monochrome image is to do
[rows, columns, numberOfColorChannels] = size(yourImage);

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