Effacer les filtres
Effacer les filtres

Simplify Matrix decimal to integers

3 vues (au cours des 30 derniers jours)
Shaunak Bagade
Shaunak Bagade le 19 Oct 2021
I do not want
881/2158 985/1393 780/1351
881/2158 -985/1393 780/1351
-881/1079 0 780/1351
But I want
1 1 1
1 -1 1
-2 0 1
How do I do this using one single function ?
I get this error if I use simplify
Check for incorrect argument data type or missing argument in call to function 'simplify'.

Réponses (2)

Alan Stevens
Alan Stevens le 19 Oct 2021
Modifié(e) : Alan Stevens le 19 Oct 2021
One way is
M = [881/2158 985/1393 780/1351
881/2158 -985/1393 780/1351
-881/1079 0 780/1351]
M = 3×3
0.4082 0.7071 0.5774 0.4082 -0.7071 0.5774 -0.8165 0 0.5774
ip = find(M>=0);
in = find(M<0);
M(ip) = ceil(M(ip));
M(in) = floor(M(in));
disp(M)
1 1 1 1 -1 1 -1 0 1
Don't know where you got the -2 from though!
  1 commentaire
Shaunak Bagade
Shaunak Bagade le 19 Oct 2021
I don't want to round the numbers ... I need to simplify it like 881/2158 is common factor in column 1 ... 985/1393 in column 2 ... 780/1351 in column 3

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Cris LaPierre
Cris LaPierre le 19 Oct 2021
Modifié(e) : Cris LaPierre le 19 Oct 2021
It's likely going to take two functions: one to convert your symbolic expressions to numeric, and a second to round.
I would probably do something like
new_var = round(double(old_var))
  5 commentaires
Steven Lord
Steven Lord le 19 Oct 2021
Or you could normalize by the first element in each column.
M = [881/2158 985/1393 780/1351
881/2158 -985/1393 780/1351
-881/1079 0 780/1351];
B = normalize(M, 1, 'scale', 'first') % Normalize in dimension 1
B = 3×3
1 1 1 1 -1 1 -2 0 1
Shaunak Bagade
Shaunak Bagade le 19 Oct 2021
Modifié(e) : Shaunak Bagade le 22 Oct 2021
Thanks But now we know M but what if we need to normalize it when M is not known

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