How to vectorize this code?

I try to use bsxfun, but maybe it does not suit this purpose.
C = bsxfun(@function,A(AIterator),cell2mat(B(BIterator)))
A is n*6, where the iterator runs on n, and B is a cell with 3*3 doubles (length m). Thanks for the help.

5 commentaires

Star Strider
Star Strider le 26 Oct 2014
Please enlighten us!
What do you want to do? (A bit more of your code prior to the line you posted may help explain that.) Include whatever defines ‘AIterator’ and ‘BIterator’
What does ‘function’ do?
If your code is throwing errors, please copy and paste into your Question the complete text of the error messages, and the line that is throwing the error.
UCL student
UCL student le 26 Oct 2014
Iterators loop A and B like colons do.
The error is: Non-singleton dimensions of the two input arrays must match each other.
The function calculates an array based on the 6; and 3*3 doubles.
Hope this helps.
Or with simple loops:
for AIterator = 1:size(A,1)
for BIterator = 1:size(B,1);
outM{AIterator,BIterator} = function(A(AIterator,:), cell2mat(B(BIterator)));
end
end
Jan
Jan le 26 Oct 2014
I'm deeply confused. What is the meaning of:
The function calculates an array based on the 6; and 3*3 doubles.
?? Please post a minimal running example, which demonstrates your problem.
So, simplified:
A = zeros(100,6);
B = zeros(3,3);
celll = cell(28);
for l = 1:28
celll{l} = B;
end
outM = cell(size(A,1),size(B,1));
for AIterator = 1:size(A,1)
for BIterator = 1:size(B,1);
outM{AIterator,BIterator} = blackboxfunc(A(AIterator,:), cell2mat(celll(BIterator)));
end
end
Blackboxfunc is unknown for me, I try to test how to call that (computational time). I even would like to test it using the gpu.

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Réponses (1)

Guillaume
Guillaume le 26 Oct 2014

0 votes

bsxfun can only return matrices, not cell arrays, and only operates on matrices as well. If your output has to be a cell array, you can't use bsxfun.
Without knowing more about function, the best that you could do is vectorise the inner loop with:
outM(AIterator, :) = cellfun(@(b) function(A(AIterator, :), cell2mat(b), B, 'UniformOutput', false);

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le 27 Oct 2014

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