Function output is only ans, how do it get output as variable?

4 vues (au cours des 30 derniers jours)
Brian
Brian le 26 Oct 2014
Commenté : Jan le 26 Oct 2014
Hi, I know this is probably a simple fix, but i just started using MATLAB, and am having trouble getting my function to output something other than ans. Here is my code, the input that I am using is x=(0:.01:50) and r=.5:
function [y,dy] = func(x,r)
y=((1+r)*exp((x)))./(1+(r*(exp((1+r)*((x))))));
dy= ((1+(r*(exp((1+r)*((x)))))* (diff(((1+r)*exp((x)))))-((1+r)*exp((x)))* diff((1+(r*(exp((1+r)*((x)))))))))/((1+(r*(exp((1+r)*((x))))))^2);
end
since I am defining y and dy, I thought each answer would be in its own matrix.
  1 commentaire
Jan
Jan le 26 Oct 2014
Star Stride hit the point: You have to call your function exactly as you assign the values to y and dy in your code and as you use the built-in functions exp, +, *, ./, diff and ^.
Such basic questions are explained exhaustively in teh Getting Started chapters of the documentation. It is recommended to study them carefully.

Connectez-vous pour commenter.

Réponses (1)

Star Strider
Star Strider le 26 Oct 2014
The both should appear if you ask them to.
Try this:
x=(0:.01:50);
r=.5;
[y,dy] = func(x,r)

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by