3D plot represented in 2D
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Hello,
I am trying to find a way to make the results of my 3D plot more visible. I see two ways to do that: make a border to different datasets or to make z-axes values distribution as a bacground in 2D image of x and y? Do you have an idea how to do that?
Now I have this dataset, which gives points on 3D graph.
Thanks for your help.
x1 = [1.15 1.24 1.19];
y1 = [191.00 187.90 173.30];
z1 = [168.70 175.70 155.10];
scatter3(x1,y1,z1)
xlabel('e')
ylabel('S')
zlabel('Wf')
grid on
hold on
x2 = [1.18 1.35 1.34];
y2 = [207.20 210.40 188.80];
z2 = [183.60 201.90 184.60];
scatter3(x2,y2,z2)
xlabel('e')
ylabel('S')
zlabel('Wf')
grid on
hold on
x3 = [0.65 0.92 1.33];
y3 = [258.10 211.90 192.20];
z3 = [138.20 152.60 197.30];
scatter3(x3,y3,z3)
xlabel('e')
ylabel('S')
zlabel('Wf')
grid on
hold on
x3 = [0.65 0.92 1.33];
y3 = [258.10 211.90 192.20];
z3 = [138.20 152.60 197.30];
scatter3(x3,y3,z3)
xlabel('e')
ylabel('S')
zlabel('Wf')
grid on
hold on
x4 = [0.65 0.76 0.74];
y4 = [394.73 146.90 428.90];
z4 = [196.30 236.60 273.70];
scatter3(x4,y4,z4)
xlabel('e')
ylabel('S')
zlabel('Wf')
grid on
hold on
x5 = [0.59 0.98 1.25];
y5 = [327.90 309.10 363.00];
z5 = [156.40 221.70 317.30];
scatter3(x5,y5,z5)
xlabel('e')
ylabel('S')
zlabel('Wf')
grid on
hold on
x6 = [0.54 0.60 0.79];
y6 = [308.80 244.20 245.70];
z6 = [133.60 109.70 156.10];
scatter3(x6,y6,z6)
xlabel('e')
ylabel('S')
zlabel('Wf')
grid on
hold on
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Réponses (1)
Cris LaPierre
le 28 Jan 2022
x1 = [1.15 1.24 1.19];
y1 = [191.00 187.90 173.30];
z1 = [168.70 175.70 155.10];
stem3(x1,y1,z1)
xlabel('e')
ylabel('S')
zlabel('Wf')
grid on
hold on
x2 = [1.18 1.35 1.34];
y2 = [207.20 210.40 188.80];
z2 = [183.60 201.90 184.60];
stem3(x2,y2,z2)
x3 = [0.65 0.92 1.33];
y3 = [258.10 211.90 192.20];
z3 = [138.20 152.60 197.30];
stem3(x3,y3,z3)
x3 = [0.65 0.92 1.33];
y3 = [258.10 211.90 192.20];
z3 = [138.20 152.60 197.30];
stem3(x3,y3,z3)
x4 = [0.65 0.76 0.74];
y4 = [394.73 146.90 428.90];
z4 = [196.30 236.60 273.70];
stem3(x4,y4,z4)
x5 = [0.59 0.98 1.25];
y5 = [327.90 309.10 363.00];
z5 = [156.40 221.70 317.30];
stem3(x5,y5,z5)
x6 = [0.54 0.60 0.79];
y6 = [308.80 244.20 245.70];
z6 = [133.60 109.70 156.10];
stem3(x6,y6,z6)
hold off
4 commentaires
Star Strider
le 28 Jan 2022
@Mariia Arseenko — Accepting Cris’s Answer is the best way to express your thanks.
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