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(Simple) How to solve basic equation

6 vues (au cours des 30 derniers jours)
A
A le 25 Nov 2014
Wondering if someone can help me find the error in this simple code. I'm trying to solve for N in terms of b and bt.
sym b bt N
k = 1/24;
l = (b + 0.5)/(6 + 12*b);
m = (b^2 + b/2)/(2 + 4*b);
q = ( (-k+l+m) + bt*(-4*k+3*l+2*m) )/ (1 + 2*bt);
eqn = -1/336 - l/24 + (6/5)*l^2 + 3*m/10 + 2*m*l + (2/3)*m^2 - q/6 - bt*q/6 + (3*l*q + 2*m*q)*(1+bt) == 1/N;
s = solve(eqn, N)

Réponse acceptée

Star Strider
Star Strider le 25 Nov 2014
In R2014b, you have to replace ‘sym’ with ‘syms’. Otherwise, all you need to do is to add collect and simplify calls to get a simplified result:
s = solve(eqn, N)
s = simplify(collect(s),'steps',10)
produces:
s =
10080/((1260*bt + 1680)*b^2 + (420*bt + 1596)*b + 35*bt + 54)
  2 commentaires
A
A le 26 Nov 2014
This is exactly what I needed, thank you very much! Appreciate the simplify function also.
Star Strider
Star Strider le 26 Nov 2014
My pleasure!

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Amutha S
Amutha S le 16 Déc 2020
sym b bt N
k = 1/24;
l = (b + 0.5)/(6 + 12*b);
m = (b^2 + b/2)/(2 + 4*b);
q = ( (-k+l+m) + bt*(-4*k+3*l+2*m) )/ (1 + 2*bt);
eqn = -1/336 - l/24 + (6/5)*l^2 + 3*m/10 + 2*m*l + (2/3)*m^2 - q/6 - bt*q/6 + (3*l*q + 2*m*q)*(1+bt) == 1/N;
s = solve(eqn, N)

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