Find value of x from curve

1 vue (au cours des 30 derniers jours)
abbas hasan
abbas hasan le 1 Déc 2014
Commenté : Star Strider le 1 Déc 2014
hi, i had values of y from 0 to 2pi, related to x values from 0 to 10 with step 0.5; i.e., i calculated the value of y using program for the values of x=0:0.5:10. i want to find the value of x from the plot(x,y), for cer
x=0:0.5:10;
y=0 0.383135237593798 0.762305633253970 1.12500381866696 1.47841592230188 1.82360426305799 2.16799972102249 2.50162151353647 2.83129834831420 3.15388959500014 3.47113990999891 3.77183336056194 4.06431023145887 4.35173946610087 4.63997932479654 4.92354827732318 5.20849294256939 5.49434987763603 5.77926587166893 5.77926587166893 6.28318530717959
find x for values of y=0 1.57079632679490 3.14159265358979 4.71238898038469;
thanks a lot for any helps

Réponse acceptée

Star Strider
Star Strider le 1 Déc 2014
Modifié(e) : Star Strider le 1 Déc 2014
Use interp1, interpolating on the y values, reversing the x and y arguments. Your data contain two identical y-values, so it is necessary to cheat a bit and add a very small value (I chose 1E-15) to make them monotonically increasing in y. I sorted them first to be certain I wasn’t missing any of the repeated values:
x = 0:0.5:10;
y = [0 0.383135237593798 0.762305633253970 1.12500381866696 1.47841592230188 1.82360426305799 2.16799972102249 2.50162151353647 2.83129834831420 3.15388959500014 3.47113990999891 3.77183336056194 4.06431023145887 4.35173946610087 4.63997932479654 4.92354827732318 5.20849294256939 5.49434987763603 5.77926587166893 5.77926587166893 6.28318530717959];
yq = [0 1.57079632679490 3.14159265358979 4.71238898038469]; % Query Points
xy = [x' y']; % Create MAtrix For Sorting
[xys, idx] = sortrows(xy,2); % Sort
dup = find(diff([xys(:,2)]) == 0)+1; % Find Non-Increasing Values
xys(dup,2) = xys(dup,2) + [1:length(dup)]*1E-15; % Add ‘1E-15’ To Duplicates
xq = interp1(xys(:,2), xys(:,1), yq); % Interpolate To Find ‘x’ Values
figure(1)
plot(x, y, 'g')
hold on
plot(xq, yq, 'mp')
hold off
The ‘xq’ variable holds the x values you want that correspond to the y values in ‘yq’. The plot shows them.
  2 commentaires
abbas hasan
abbas hasan le 1 Déc 2014
thanks a lot, this correct answer i am very grateful for your help
Star Strider
Star Strider le 1 Déc 2014
My pleasure!

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Interpolation dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by