Something is wrong with my FFT results

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Nathan Lively
Nathan Lively le 9 Mar 2022
I've been over this for a couple of hours and I can't find where the error is. I just want to confirm that at each step of the process that I'm doing it correctly so all of the outputs should match.
  1. Import loudspeaker response data in magnitude and phase.
  2. Convert to complex number.
  3. Interpolate.
  4. IFFT
The first three steps return matching plots, but the plot of the fourth step has something wrong with it. What am I doing wrong??
And here's the magPhase2complex function I made:
function Z = magPhase2complex(mag_dB,phase_deg)
Z = [db2mag(mag_dB) .* exp(1j*(deg2rad(phase_deg)))];
some n
% Get some Data
CSVmainFile = '/Users/nathanlively/Downloads/PRX615M_Main.csv';
M_TF = readtable(CSVmainFile,'ReadVariableNames',false);
M_TF.Properties.VariableNames = {'frequency','magnitude','phase','coherence'};
% Convert to complex
M_TF.Z = magPhase2complex(M_TF.magnitude,M_TF.phase);
% Interpolate and fill missing
newFs = 192000;
main = timetable('SampleRate',newFs);
main.Hz = linspace(0,newFs,newFs)';
main.Z = interp1(M_TF.frequency,M_TF.Z,main.Hz,'pchip',NaN);
main.Z = fillmissing(main.Z,'nearest','EndValues','extrap');
main.magnitude = mag2db(abs(main.Z));
main.IR = real(ifft(main.Z)) * height(main);
main.Zrecon = fft(main.IR) / height(main);
main.magnitudeRecon = mag2db(2*abs(main.Zrecon));
semilogx(M_TF.frequency,M_TF.magnitude, main.Hz,main.magnitude, main.Hz,main.magnitudeRecon)
xlim([20 20000]);ylim([max(M_TF.magnitude)-10 max(M_TF.magnitude)]);
legend('original','interp1','reconstructed magnitude','FontSize',22)
  16 commentaires
Bjorn Gustavsson
Bjorn Gustavsson le 10 Mar 2022
@Chris Turnes - fair points, the question just struck me as I read your description, and thought that "the optimal procedure surely ought to be the averages of the real and the conjugated complex parts". But I see the use-case and that my flicker of an idea doesn't really apply...
Nathan Lively
Nathan Lively le 10 Mar 2022
@Paul Generate a new spectrum, that starts at f =,0, is equally spaced at 1 Hz, and finishes at Fs/2 = 192000/2?
If so what is the use of that end product?
One of the problems I was running into is that I want to window the IFFT data at a specific lenght in milliseconds. With the "dirty" data I am not able to calculate the time vector to go along with the IFFT.

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Nathan Lively
Nathan Lively le 10 Mar 2022
Although I'm not 100% this is correct, so far the answer I mentioned in this comment seems to be working. I just needed to replace the beginning and end values with zeros.

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