how to floor time for each hour?

6 vues (au cours des 30 derniers jours)
Lilya
Lilya le 15 Mar 2022
Commenté : Lilya le 17 Mar 2022
Hi Experts,
I have this time format, and i want to have the time only for each hour. Could anyone please help with this?
'12-Dec-2021 09:09:04'
'12-Dec-2021 09:24:04'
'12-Dec-2021 09:39:04'
'12-Dec-2021 09:54:04'
Much appreciated
  2 commentaires
KSSV
KSSV le 15 Mar 2022
What's your desired output?
Lilya
Lilya le 16 Mar 2022
to have the data at each hour instead of having different time steps for each hour

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Réponse acceptée

Star Strider
Star Strider le 15 Mar 2022
Try this —
tv = {'12-Dec-2021 09:09:04'
'12-Dec-2021 09:24:04'
'12-Dec-2021 09:39:04'
'12-Dec-2021 09:54:04'};
dtv = datetime(tv, 'Format','dd-MMM-yyyy HH') % Display Only The Hour
dtv = 4×1 datetime array
12-Dec-2021 09 12-Dec-2021 09 12-Dec-2021 09 12-Dec-2021 09
dtv = datetime(tv, 'Format','dd-MMM-yyyy HH:00:00') % Display Hour, Set Rest To Zeros
dtv = 4×1 datetime array
12-Dec-2021 09:00:00 12-Dec-2021 09:00:00 12-Dec-2021 09:00:00 12-Dec-2021 09:00:00
The 'Format' name-value pair controls the display, so set it however you want it.
.
  3 commentaires
Star Strider
Star Strider le 16 Mar 2022
Modifié(e) : Star Strider le 16 Mar 2022
As always, my pleasure!
EDIT — (16 Mar 2022 at 12:40)
To summarise the data for each hour, use the table2timetable function and then the retime function.
.
Lilya
Lilya le 16 Mar 2022
Noted

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Plus de réponses (2)

Steven Lord
Steven Lord le 15 Mar 2022
If you want to actually modify the data rather than just changing how the data is displayed you can use dateshift.
tv = {'12-Dec-2021 09:00:00',
'12-Dec-2021 09:09:04'
'12-Dec-2021 09:24:04'
'12-Dec-2021 09:39:04'
'12-Dec-2021 09:54:04'};
dtv = datetime(tv)
dtv = 5×1 datetime array
12-Dec-2021 09:00:00 12-Dec-2021 09:09:04 12-Dec-2021 09:24:04 12-Dec-2021 09:39:04 12-Dec-2021 09:54:04
dtv2 = dateshift(dtv, 'start', 'hour')
dtv2 = 5×1 datetime array
12-Dec-2021 09:00:00 12-Dec-2021 09:00:00 12-Dec-2021 09:00:00 12-Dec-2021 09:00:00 12-Dec-2021 09:00:00
To check that the data has actually been changed:
dtv2 == dtv(1)
ans = 5×1 logical array
1 1 1 1 1
  3 commentaires
Steven Lord
Steven Lord le 16 Mar 2022
Based on your answer to KSSV's comment "to have the data at each hour instead of having different time steps for each hour" I suspect that storing your data in a timetable array and using retime to retime it to an hourly basis might be a solution to your larger problem.
Lilya
Lilya le 17 Mar 2022
yes.. I did that and it works perfectly!
thank you very very much.

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Arif Hoq
Arif Hoq le 15 Mar 2022
A={'12-Dec-2021 09:09:04'
'12-Dec-2021 09:24:04'
'12-Dec-2021 09:39:04'
'12-Dec-2021 09:54:04'};
B=datetime(A,'Format','hh') % if only hour
B1=datetime(A,'Format','hh:mm:ss') % if hour,min,sec
  1 commentaire
Lilya
Lilya le 16 Mar 2022
Thanks Arif.. appreciated

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