How to bold in a sprintf function?

For below, m and b are going to be numbers, how can i make only those parts of the statement bold? I know its \bf somewhere but i couldnt get it to work.

sprintf('Y = %.2f X + %.2f',m,b)

As a follow up, I also have this where im trying to make every 0 or multiple of 10 bold on the x-axis, how can i incoorporate that? This is what i have, once again could get \bf to work anywhere

endAt = length(myAx.XAxis.TickLabels)

for i=0:10:endAt
    myAx.XAxis.TickLabels{0} = i;
end 

Answer 1

[Star Strider]

You can do that in a a text call (with any text objects, such as title, xlabel, etc.), nowhere else.

m = pi;
b = exp(1);
text(0.3, 0.7, sprintf('Y = \\bf%.2f\\rm X + \\bf%.2f\\rm',m,b))

.

[Elena]

ah thank you!!

[Star Strider]

As always, my pleasure!

Answer 2

[Voss]

m = 2;
b = 1;
% set up normal and bold strings, for comparison:
str_normal = sprintf('Y = %.2f X + %.2f',m,b)

str_normal = 'Y = 2.00 X + 1.00'

% use \\ to "escape" the \, i.e., allow a backslash to "pass-through" sprintf()
% without interpretation:
str_bold = sprintf('Y = {\\bf%.2f} X + {\\bf%.2f}',m,b)

str_bold = 'Y = {\bf2.00} X + {\bf1.00}'

% make some lines to put in a legend, using str_normal and str_bold as
% their names:
x = 0:30;
h_normal = plot(x,m*x+b);
hold on
h_bold = plot(x,m*x+b);
legend([h_normal h_bold],{str_normal str_bold});

% set up the XTickLabels:
xtick_label = cell(size(x));
for ii = 1:numel(x)
    if mod(x(ii),10) == 0 % x(ii) is a multiple of 10 (0 is a multiple of 10 too)
        xtick_label{ii} = sprintf('{\\bf%d}',x(ii));
    else
        xtick_label{ii} = sprintf('%d',x(ii));
    end
end
set(gca(),'XTick',x,'XTickLabel',xtick_label)

Answer 3

[Jan]

Ticks = linspace(0, 30, 7);
ax = axes('XLim', [0, 30], 'XTick', Ticks, ...
    'TickLabelInterpreter', 'latex');

for k = 1:numel(Ticks)
    if rem(Ticks(k), 10) == 0
        ax.XAxis.TickLabels{k} = ['\bf' ax.XAxis.TickLabels{k}];
    end
end

% Or without a loop:
m = (rem(Ticks, 10) == 0);
ax.XAxis.TickLabels(m) = strcat('\bf', ax.XAxis.TickLabels(m)):

[Elena]

thank you! i just realised i can only accept one answer but i really appreciate it

[Jan]

@Elena: You are welcome.

Accepting one answer is fine. The main point of accepting is to indicate, that this question does not need further attention. I have more points than I can eat, so I'm glad, if I can help to solve the problems. :-)