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Effacer les filtres

I want to change the color of the markers in scatter plot which are below the function line

4 vues (au cours des 30 derniers jours)
I have the following code
clc
clear
close all
d = 4;
N = 1000;
X = linspace(0,d,N);
func = @(X) 2*X.*cos(X.^2).*exp(sin(X.^2)) + 14;
limit = func(X);
x = 4*rand(1,N);
y = 25*rand(1,N);
figure(1),hold on
h = scatter(x,y,10,'markerfacecolor','b');
plot(X,limit,'k-','linew',1.3)
for i = 1:N
if any(y(i) < limit)
set(h,'YData','MarkerFaceColor','r','Markeredgecolor','r')
end
end
but it keeps giving the following error
Error using matlab.graphics.chart.primitive.Scatter/set
Invalid parameter/value pair arguments.
Any help would be appreciated

Réponse acceptée

Star Strider
Star Strider le 11 Avr 2022
d = 4;
N = 1000;
X = linspace(0,d,N);
func = @(X) 2*X.*cos(X.^2).*exp(sin(X.^2)) + 14;
limit = func(X);
x = 4*rand(1,N);
y = 25*rand(1,N);
figure(1)
hold on
scatter(x,y,10,'markerfacecolor','b');
Lv = y < func(x); % Logical Vector Based On 'func' Value At Each 'x'
scatter(x(Lv),y(Lv),10,'MarkerFaceColor','r','Markeredgecolor','r')
plot(X,limit,'k-','linew',1.3)
.
  2 commentaires
Haseeb Hashim
Haseeb Hashim le 11 Avr 2022
Hi Great work. Can you please explain these lines expecially the first one
Lv = y < func(x);
scatter(x(Lv),y(Lv),10,'MarkerFaceColor','r','Markeredgecolor','r')
Star Strider
Star Strider le 11 Avr 2022
Thank you!
Sure!
The ‘Lv’ variable is a logical vector that calculates the value of ‘func’ at each ‘x’ value and compares that result with the corresponding ‘y’ value. If that ‘y’ value is less than ‘func(x)’, that value of ‘Lv’ is set to true. (It definitely helps that ‘func’ is an anonymous function in your original code, making this straightforward.)
The scatter call just after that uses ‘Lv’ to refer to the individual ‘x’ and ‘y’ values, plotting only those that are true as defined by ‘Lv’.

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Plus de réponses (1)

MJFcoNaN
MJFcoNaN le 11 Avr 2022
You can try this:
clc
clear
close all
d = 4;
N = 1000;
X = linspace(0,d,N);
func = @(X) 2*X.*cos(X.^2).*exp(sin(X.^2)) + 14;
limit = func(X);
x = 4*rand(1,N);
y = 25*rand(1,N);
ind_r = y < limit;
c=zeros(N,3);
% red
c(ind_r, 1)=1;
% blue
c(~ind_r, 3)=1;
figure(1),hold on
h = scatter(x,y,10,c);
plot(X,limit,'k-','linew',1.3)
  2 commentaires
Haseeb Hashim
Haseeb Hashim le 11 Avr 2022
Now I get it we cant check the particular random against every number of function value because in this case the random numbers greater than the greatest number in function values will be turned blue otherwise they will be all read
MJFcoNaN
MJFcoNaN le 11 Avr 2022
Why do you make both x and y random?
If your task allows one random value, for example x=X, it may give out a more "reasonable" result, which achieves the same algorithm as the other answer.

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