Need to implement a parameter that grows at a specific rate over time

4 vues (au cours des 30 derniers jours)
Michael Reed
Michael Reed le 27 Avr 2022
Commenté : Star Strider le 27 Avr 2022
The context is a computational general equilibrium (economic) model
I want to have a parameter that is geometric growth.
The growth in time is G(+1) = (1+I)*G, however, I don't know how to set the value of G at t=0?
(I is percent growth of G for each time period)
I looked in help and found the following equation form
y=C*exp(k*t)
where C is the value of y at t=0 and k can be derived by knowing the value of y at a different time
However, I'm a nube and I'm not sure how to implement this equation in the context of my model.
  2 commentaires
Mathieu NOE
Mathieu NOE le 27 Avr 2022
hello
does it mean you know G for t > 0 ? but not at t = 0 ?
Michael Reed
Michael Reed le 27 Avr 2022
i know G(0) for example G(0) = 2.0, and I also know I (0.3). I want these two values to be input parameters
In algabraic form the equation is
G(t) = G(0)*(1+I)^t
Im not sure how to implement t in the exponent

Connectez-vous pour commenter.

Réponses (1)

Star Strider
Star Strider le 27 Avr 2022
Perhaps this —
G0 = 2;
I0 = 0.3;
Gfcn = @(t,G,I) G.*(1+I).^t;
t = linspace(0,5, 25);
figure
plot(t, Gfcn(t,G0,I0))
grid
xlabel('t')
ylabel('G(t)')
.
  4 commentaires
Michael Reed
Michael Reed le 27 Avr 2022
I may have a solution. I will implement it later today and let you know my results.
Thanks for the info in above answers. It is useful

Connectez-vous pour commenter.

Catégories

En savoir plus sur Octave dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by