Error: Function definitions are not permitted in this context.
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This is my function
function [ area ] = calcarea(rad )
area = pi*rad.^2
end
When I try to run it, following message shows up, "The selected section cannot be evaluated because it contains an invalid statement
Also, the command window says "Error: Function definitions are not permitted in this context"
What am I doing wrong???
1 commentaire
Nabin SUNAM
le 23 Jan 2015
Réponse acceptée
Plus de réponses (5)
Star Strider
le 22 Jan 2015
You have to put functions such as yours in their own separate .m-files. In your situation, you would save it as: calcarea.m, and to run it from your main script, you would call it as:
area = calcarea(rad)
bahadir safak
le 17 Déc 2016
Modifié(e) : Walter Roberson
le 6 Mar 2018
sigma=1;
thresh=1000;
disp=1;
radius=1
im=imread('11.jpg');
function [cim, r, c] = harris(im, sigma, thresh, radius, disp)
error(nargchk(2,5,nargin));
dx = [-1 0 1; -1 0 1; -1 0 1]; % Derivative masks
dy = dx';
Ix = conv2(im, dx, 'same'); % Image derivatives
Iy = conv2(im, dy, 'same');
??? Error: File: harris1.m Line: 45 Column: 1
Function definitions are not permitted in this context.
>>
???
7 commentaires
Image Analyst
le 17 Déc 2016
You can't have a script, followed by a function in the same file. But you can have two functions, so add this to the top of the file
function harris1()
or else split those up into two different files.
bahadir safak
le 17 Déc 2016
Modifié(e) : Walter Roberson
le 6 Mar 2018
function harris1()
sigma=1;
thresh=1000;
disp=1;
radius=1;
im=imread('11.jpg');
function [cim, r, c] = harris(im, sigma, thresh, radius, disp)
error(nargchk(2,5,nargin));
dx = [-1 0 1; -1 0 1; -1 0 1]; % Derivative masks
dy = dx';
Ix = conv2(im, dx, 'same'); % Image derivatives
Iy = conv2(im, dy, 'same');
NOT Working!!
Image Analyst
le 17 Déc 2016
Of course not bahadir. You never even called harris() in your main program! Not only that, but you didn't even define what your output variables are. Try this:
function harris1()
clc;
sigma=1;
thresh=1000;
disp=1;
radius=1;
im=imread('cameraman.tif');
dblIm = double(im);
[cim, r, c] = harris(dblIm, sigma, thresh, radius, disp);
function [cim, r, c] = harris(im, sigma, thresh, radius, disp)
error(nargchk(2,5,nargin));
dx = [-1 0 1; -1 0 1; -1 0 1]; % Derivative masks
dy = dx';
Ix = conv2(im, dx, 'same'); % Image derivatives
Iy = conv2(im, dy, 'same');
% Define output variables.
cim = rand % Whatever it's supposed to be....
r = rand
c = rand
Mohammedashraf Shaikh
le 4 Mai 2017
Modifié(e) : Walter Roberson
le 6 Mar 2018
function[d] = hcompare_EMD(h1,h2)
d = sum(abs(cumsum(h1) - cumsum(h2)));
end
img = imread('C:\Users\Hp\Desktop\col\001.jpg');
function[h] = histImage(img)
% This function calculates normalized histogram of image.
% Normalized histogram is histogram h, that has at
% each i place in it, value:
% (number of picture pixels with gray level i-1) /
% (total num of pixels in picture).
sum = 0;
[y,x] = size(img); % getting sizes of image
h = zeros(1,256); % creating output histogram array
for i = 1:1: y % runing on rows
for j = 1:1: x % running on colomns
% gray level is addtess to cell in output histogram array
% we add there 1 (bacause of current pixel (y,x) has this gray level
h(img(i,j)) = h(img(i,j)) + 1;
% pay attention to fact, that we use here pixel value as index!
end
end
h = h./(y*x);
end
% to calculate the distance between the histograms of the two images %%
%(histArray, histPattern):
function[dmap] = patDistMAp(histArray, histPattern)
[y,x,z] = size(histArray);
dmap = zeros(y,x); % output array
for i = 1:1: y % runing on rows
for j = 1:1: x % running on colomns
hist = histArray(i,j,:);
% for k = 1:1:256 % making array 1x256 from 1x1x256
% h1(k) = hist(1,1,k); % there is a permute function,
% end % but we will use it next time)
h1 = permute(squeeze(hist),[2,1]);
% Using temp variable, as MATLAB7 wants it:
temp = hcompare_EMD(histPattern,h1);
dmap(i,j) = temp;
end
end
end
Mohammedashraf Shaikh
le 4 Mai 2017
Modifié(e) : Mohammedashraf Shaikh
le 4 Mai 2017
in above problem i am getting problem
function[d] = hcompare_EMD(h1,h2) |
Error: Function definitions are not permitted in this context.
@Mohammedashraf Shaikh: your code is badly aligned, and this makes hiding the errors easy. Once I correctly aligned your code and put each operation on its own line, then the (first) mistake is obvious, and occurs in the first five lines of code:
function[d] = hcompare_EMD(h1,h2)
d = sum(abs(cumsum(h1) - cumsum(h2)));
end
img = imread('C:\Users\Hp\Desktop\col\001.jpg');
function[h] = histImage(img)
...
You call img = ... outside of any function.
It is also possible that your first function definition occurs after some lines of code in a script. Depending on MATLAB version, this will also cause an error. See the other answers for more info on this.
Summary: Learn to align your code consistently (use the MATLAB defaults), and do not put multiple operators onto one line (especially the end for functions!). You can automatically align the code in the MATLAB Editor: select all code, then press ctrl+i.
Image Analyst
le 4 Mai 2017
Rwigema james
le 7 Juil 2017
Modifié(e) : Image Analyst
le 7 Juil 2017
function Iout = readAndPreprocessImage(filename)
I=imread(filename);
if ismatrix(I)
I = cat(3,I,I,I);
end
Iout = imresize(I,[227 227]);
end
Why am I getting this error?????
Function definitions are not permitted in this context.
2 commentaires
Image Analyst
le 7 Juil 2017
You're putting the function definition in a place where it does not belong, such as below a script in release R2016a and earlier, or elsewhere.
Abbas Khreis
le 16 Mai 2021
i have 2016a version and the error Function definitions are not permitted in this con
plz help me
Elena MEZZAPESA
le 16 Nov 2017
0 votes
Hello, Did you solve the issues to this problem in the end? As of 2017 I still get this error ?! I am trying to understand if it is because I am using a trial version of the software. Best regards,
Elena
1 commentaire
Image Analyst
le 16 Nov 2017
It was masked as being solved. The trial version is no different than a full version other than being time-limited to 30 days. We'd have to see your code to figure out what's going wrong with your program.
Frieder Wittmann
le 27 Mai 2018
0 votes
This is one of the main disadvantages of MATLAB notebooks over Jupyter (python) notebooks. If I can't define functions in the middle of a script, the notebook becomes hard to read.
6 commentaires
Walter Roberson
le 27 Mai 2018
Since R2016b, MATLAB has permitted functions to be defined inside script files.
Abbas Khreis
le 16 Mai 2021
clc
clear all
function y=BUBBLE_SORT(x)
N= length(x);
if N<2
y=x;
return;
end
for i=1:N-1 ;
if(x(i)>x(i+1))
t=x(i);
x(i)=x(i+1);
x(i+1)=t;
end
end
y=BUBBLE_SORT(x(1:N-1));
y=[y x(N)];
end
this code giving me error
'''Error: File: BUBBLE_SORT.m Line: 3 Column: 11
Function definitions are not permitted in this context.'''
Walter Roberson
le 16 Mai 2021
Modifié(e) : Walter Roberson
le 17 Mai 2021
You are using R2016a or earlier, which did not permit functions to be mixed with scripts.
If you had been using R2016b or later, you would have seen a different error, complaining about function name conflicts. In versions that permit a function to be defined in a script file, it is not permitted for one of the functions to have the ame name as the script file.
Frieder Wittmann
le 17 Mai 2021
Hi thanks for your reply. Im using R2019a. Here is an example. Filename is test.m
a = 5
b = 10
function y = multiplyNumbers(a,b)
y = a * b;
end
y = multiplyNumbers(a,b)
Error: File: test.m Line: 8 Column: 1
Function definitions in a script must appear at the end of the file.
Move all statements after the "multiplyNumbers" function definition to before the first local function definition.
----
Moving the function defintion to the end of the script forces the reader to jump around. At first they might not even realize, that it's a costum function that they will find at the end of the script. In Jupyter the equivalent of the above script would have worked.
Walter Roberson
le 17 Mai 2021
MATLAB is not Jupityr.
Frieder Wittmann
le 17 Mai 2021
Modifié(e) : Frieder Wittmann
le 17 Mai 2021
It isn't, it's one of the most common competitors.
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