# Find rows based on set of values/codes

2 views (last 30 days)
Millie Johnston on 13 Sep 2022
Commented: Star Strider on 14 Sep 2022
Hello community,
I have a data set that is 48x14 (called data for this example). Each row has a set of codes (possible codes are 0 1 13 14 15 16 31 42 53 54). a row might look like this: [1 0 0 13 0 0 31 0 0 0 42 0 0 53].
The code is part of a for loop but I am strugglig with one specific part: I want to find rows that have a specific series of codes while ignoing the 0 codes. I thought the following code would work to find rows with the codes 1 13 31 42 and 53 in it:
for i = 1:length(data(:,1))
if all(data(i,find(data(i,:) == [1 13 31 42 53])))
.......
.......
I get the following error:
Arrays have incompatible sizes for this operation.
Any help would be much appreciated!

Star Strider on 13 Sep 2022
I am not certain what you want, however the ismember function might be a better option than find for this, especially since everything seems to be integers, so no floating-point approximation problems will be present (requiring ismembertol and likely more coding) —
data = [1 0 0 13 0 0 31 0 0 0 42 0 0 53];
q = ismember(data, [1 13 31 42 53])
q = 1×14 logical array
1 0 0 1 0 0 1 0 0 0 1 0 0 1
v = data(q)
v = 1×5
1 13 31 42 53
Then determine what you want to do with either ‘q’ (using the nnz function could give the number of matches) or ‘v’ (the content of the matches in the vector) here.
.
Star Strider on 14 Sep 2022
As always, my pleasure!

David Hill on 13 Sep 2022
for i = 1:size(data,2)
if all(ismember(data(i,:),[0 1 13 31 42 53]))%include 0
##### 2 CommentsShowHide 1 older comment
Millie Johnston on 13 Sep 2022
I am not looking for the sequnce per say, I am looking for the rows in which those numbers appear together (in any order). Does that make more sense?

Image Analyst on 13 Sep 2022
Try this
oneRow = [1 0 0 13 0 0 31 0 0 0 42 0 0 53];
oneRow(oneRow == 0) = [] % Remove zeros
oneRow = 1×5
1 13 31 42 53
In addition you should be using isequal
% Define the specific sequence you are looking for.
desiredCodeSequence = [1 13 31 42 53]; % Row should be exactly this.
% See if it matches your zero-removed row.
if isequal(oneRow, desiredCodeSequence)
% Matched
fprintf('Matched.\n')
else
% The row is not the desired sequence.
fprintf('The row is not the desired sequence.\n')
end
Matched.

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