I want to shade the area between these graphs
but this certainly does not do the trick:
fill([t t(end:-1:1)],[y1 y2(end:-1:1)],'y')
I also downloaded and tried "jblill"
but that did not seem to amend the outcome so far

2 commentaires

Huijian Huang
Huijian Huang le 15 Déc 2017
have you solve this problem at the end? I am also struggling with similar situation
Image Analyst
Image Analyst le 15 Déc 2017
Yes, there were answers below, one of which he accepted though both should work.

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 Réponse acceptée

Image Analyst
Image Analyst le 28 Fév 2015

41 votes

Try using fill() instead of area():
x = 1 : 300;
curve1 = log(x);
curve2 = 2*log(x);
plot(x, curve1, 'r', 'LineWidth', 2);
hold on;
plot(x, curve2, 'b', 'LineWidth', 2);
x2 = [x, fliplr(x)];
inBetween = [curve1, fliplr(curve2)];
fill(x2, inBetween, 'g');

13 commentaires

Michiel
Michiel le 1 Mar 2015
gives the exact same plot as I posted above (although I used the graph from my original post this time, which is arbitrary)
Even if I make data that cris-crosses, it seems to work:
% Create sample data.
x = 1 : 100;
curve1 = log(x);
curve2 = log(x) + rand(1, length(x)) - 0.5;
% Plot it.
plot(x, curve1, 'r', 'LineWidth', 2);
hold on;
plot(x, curve2, 'b', 'LineWidth', 2);
x2 = [x, fliplr(x)];
inBetween = [curve1, fliplr(curve2)];
fill(x2, inBetween, 'g');
grid on;
Michiel, please attach a few of your data files so we can do it with your actual data.
Michiel
Michiel le 1 Mar 2015
I found the problem... I used a column vector instead of a row vector... had to transpose the damn thing... rookie mistake 8)
Image Analyst
Image Analyst le 1 Mar 2015
Modifié(e) : Image Analyst le 1 Mar 2015
OK. Good, so fill() worked. Can you mark my Answer as Accepted then? By the way, for column vectors, use semicolon instead of comma and flipud() instead of fliplr():
% Create sample data as column vectors.
x = [1 : 100]';
curve1 = log(x);
curve2 = log(x) + rand(length(x), 1) - 0.5;
% Plot it.
plot(x, curve1, 'r', 'LineWidth', 2);
hold on;
plot(x, curve2, 'b', 'LineWidth', 2);
% For column vectors, use flipud(), for row vectors use fliplr().
x2 = [x; flipud(x)]; % Use ; instead of ,
inBetween = [curve1; flipud(curve2)]; % Use ; instead of ,
fill(x2, inBetween, 'g');
grid on;
Hassan Raheem
Hassan Raheem le 31 Août 2017
Hi, if I have to curves , but the data for each curve differ from the another (the length is not the same) , How can I plot them? Thank you EX: x1 = read from csv file1 first column x2= read from csv file2 first column y1= read from csv file1 2nd col. y2= read from csv file2 2nd col plot(x1,y1) hold on plot (x2,y2) Then how can I shade the area between these two curves?
Julien Reynes
Julien Reynes le 17 Avr 2018
It is exactly what a wanna do, but my problem is that my two curves contain NaN (they are not continuous) So if I plot, no filling appears, just boundaries. Any idea how to solve it easily?
Tom
Tom le 1 Fév 2019
If you have data sets of different lengths in the same figure, I suggest interpolating both datasets in such a way that their x-axes are identical. Since the PLOT function implicitly interpolates the data linearly, this will not change the way your data is displayed.
If you have data that contains NaNs, what do you want to achieve? How should the filling be? Should it stop at discontinuities? Should it act as if the discontinuities aren't there?
Tilen Thaler
Tilen Thaler le 16 Fév 2022
Thank you. Exactly what I was looking for.
Roger Vegeta
Roger Vegeta le 18 Avr 2022
Does this method work when both curves have different array lenght?
MadjeKoe
MadjeKoe le 17 Juin 2022
Does anybody maybe know how to remove the outside lines and to only plot the shade? Thank you in advance
Image Analyst
Image Analyst le 17 Juin 2022
@MadjeKoe simply don't call plot() and only call fill().
Hoping this post from 9 years ago is still monitored.
I tried the suggestion above, but instead of filling the area green, it just added thin black lines at the upper and lower bounds. What am I missing?
plot(averageFF2W5I(:,2),averageFF2W5I(:,1), 'k', 'LineWidth', 2);
plot(averageFF2W5I(:,2),averageFF2W5I(:,[8 9]), 'k--', 'LineWidth', 2);
fill([averageFF2W5I(:,2), fliplr(averageFF2W5I(:,2))], [averageFF2W5I(:,8), fliplr(averageFF2W5I(:,9))], 'g');
averageFF2W5I(:,2) = Strain Values
averageFF2W5I(:,1) = Stress Sample Mean
averageFF2W5I(:,[8 9]) = 95% Confidence Interval
I don't have your array, so I will use analogous data.
x=0:20; y=x.^.5; ci1=0.8*y; ci2=1.2*y;
fill([x, fliplr(x)], [ci1, fliplr(ci2)], 'g', EdgeColor='none');
hold on
plot(x,y, 'k', 'LineWidth', 2)
plot(x,[ci1;ci2], 'k--', 'LineWidth', 2)
I moved fill() before plot(), so that the line in the middle would not get covered by the fill. Alternatively, you could specify a semitransparent fill. I specified no edge for the fill. I added hold on after fill().

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Plus de réponses (3)

Star Strider
Star Strider le 28 Fév 2015
Modifié(e) : Star Strider le 28 Fév 2015

13 votes

Try this:
x = linspace(0,10*pi);
y1 = sin(x);
y2 = cos(x);
figure(1)
plot(x, y1)
hold on
plot(x, y2)
patch([x fliplr(x)], [y1 fliplr(y2)], 'g')
hold off
Experiment with your data to get the result you want.

10 commentaires

Michiel
Michiel le 28 Fév 2015
ttom = time vector [1:variable_interval:20]
y1 = the red line
y2 = the blue line
patch([ttom fliplr(ttom)], [y1 fliplr(y2)], 'g')
I had this before as well, somehow I'm doing it wrong
Star Strider
Star Strider le 28 Fév 2015
I would have to have your data to find out what the problem is. (If you want to attach it using the ‘paperclip’ icon, a .mat file is best.)
Since I don’t have your data, add a NaN value at the end of each of your data arrays (both x and y variables for both data sets) and see if that makes a difference. Just guessing.
Star Strider
Star Strider le 1 Mar 2015
If you would share your data, I could likely provide a definitive solution. I have no idea why your data are not working with my code.
Star Strider
Star Strider le 1 Mar 2015
Did my idea work with your transposed vectors? Mine requires row vectors as written here. I perhaps should have specified that.
DETELINA IVANOVA
DETELINA IVANOVA le 4 Avr 2018
Déplacé(e) : Adam Danz le 29 Jan 2024
I am using this last suggestion by Star Strider to plot error bar shading using patch, but in some cases I get in addition to the shading straight lines (see the third plot at the bottom in the attached figure) I have eliminated the points with NaNs. It seems ok in the other two cases (the upper plots in the same figure). What can be causing this?
James Stephenson
James Stephenson le 4 Mar 2021
This answer is too late for you, but maybe it will help others. The last point of your vector is your starting point as well, so the shaded area is doubling back to (0,0). That's why you're getting this wonkiness.
Yash Mistry
Yash Mistry le 20 Juil 2021
how can I avoid that?
Star Strider
Star Strider le 29 Fév 2024
If you have not already done so, check to see if there are NaN values in your data. One way to do that is:
NrNaNs = nnz(isnan(averageFF2W5I))
Your options then are to to remove them using the rmmissing function or interpolate them with the fillmissing function.
However, one problem is that you have column vectors, and you are using fliplr to flip a column vector. That is going to produce the same unchanged column vector, of course.
An improvement to your fill call could be:
fill([averageFF2W5I(:,2); flip(averageFF2W5I(:,2))], [averageFF2W5I(:,8); flip(averageFF2W5I(:,9))], 'g');
Note my use of the semicolon (;) vertical concatenation operator, and the generic flip function that works without further elaboration on vector arguments.
.
Jason Thomas
Jason Thomas le 29 Fév 2024
@Star Strider THANK YOU!
There were several NaN values in the confidence interval. Once I removed those with rmmissing and used your code with "flip" instead of "fliplr" it worked perfectly.
Star Strider
Star Strider le 29 Fév 2024
My pleasure!
A Vote would be appreciated!

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Javier Montalt Tordera
Javier Montalt Tordera le 12 Avr 2019

9 votes

This can be simplified using the function shade (in MATLAB File Exchange).
The syntax for the above problem would be:
shade(t,y1,t,y2,'FillType',[1 2;2 1]);
The FillType option specifies that the area between lines 1 and 2 should be filled, whether 1 is above 2 or the other way round.

5 commentaires

SEETHA JAYAN
SEETHA JAYAN le 24 Mar 2020
would you please help me ,
i used the above code to shade between min and maximum but I couldnt change edge color and face colur
Javier Montalt Tordera
Javier Montalt Tordera le 24 Mar 2020
You should be able to change line color and fill color using the properties 'Color' and 'FillColor', respectively, specified as name-value pairs.
Giacomo Giuliani
Giacomo Giuliani le 19 Mai 2022
Is it possible to fill an area between three or more curves without covering none of the curves between the edges?
Image Analyst
Image Analyst le 19 Mai 2022
@Giacomo Giuliani, yes though to not cover the line plots you might plot (or re-plot) the line plots after you've plotted the patches between the curves.
Giacomo Giuliani
Giacomo Giuliani le 19 Mai 2022
Modifié(e) : Giacomo Giuliani le 19 Mai 2022
It came to my minds one second after I posted. It works! Thanks.

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Adam Danz
Adam Danz le 29 Jan 2024

0 votes

Another solution that may be helpful is the fillBetweenAreaCurve function offered by the MATLAB Charting team on the File Exchange.

1 commentaire

Les Beckham
Les Beckham le 29 Fév 2024
FYI - it appears that this File Exchange utility requires the Mapping Toolbox.

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