how can I plot this function?

My problem is how to plot this function

5 commentaires

KALYAN ACHARJYA
KALYAN ACHARJYA le 26 Oct 2022
Niloufar
Niloufar le 26 Oct 2022
The power in denominator is two
David Hill
David Hill le 26 Oct 2022
Is it a function in f(x,r,t) or f(x,r) or f(r,t) or f(x,t) or f(x), f(r ) or f(t). What are the bounds or inputs for x, r, and t?
Niloufar
Niloufar le 27 Oct 2022
f(t) the bound for t is -5 to 5
Niloufar
Niloufar le 27 Oct 2022
close all;clear;clc; t = linspace(-5,5,1000); %ylim([-0.01 0.01]); N = 1000;
syms n t; an = (100*n*pi*(-1).^(n+1).*(1000-121*n.*n*pi*pi))/((1000-121*n.*n*pi*pi)^2 + (1320*n*pi)^2)*(50*n*pi); bn = (100*n*pi*(-1)^(n+1)*(1320*n*pi))/((1000-121*n.*n*pi*pi)^2 + (1320*n*pi)^2)*(50*n*pi); f = symsum(an.*cos(100*n*pi*t) + bn.*sin(100*n*pi*t),n,1,Inf); fplot(f);
I have done it with Symsum but it doesn't work.what is the problem

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Réponses (1)

t = linspace(-5,5,1000);
N = 1000;n=1:N;
an = (100*n*pi.*(-1).^(n+1).*(1000-121*n.^2*pi^2))/(((1000-121*n.^2*pi^2).^2 + (1320*n*pi).^2).*(50*n*pi));
bn = (100*n*pi.*(-1).^(n+1).*(1320*n*pi))./(((1000-121*n.^2*pi^2).^2 + (1320*n*pi).^2).*(50*n*pi));
f = @(t)sum(an.*cos(100*n*pi*t) + bn.*sin(100*n*pi*t));
for k=1:length(t)
F(k)=f(t(k));
end
plot(t,F)

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