Suppose I have four matrix
A,B,C and D. These all are (mx3) matrix where m is some number.
and I have to define a number as an user input which is N.
Now I want a merge matrix such that,
for N = 1
New_matrix = [A]
for N = 2
New_matrix = [A
B
C]
for N = 3
New_matrix = [A
B
C
D
A]
for N = 4
New_matrix = [A
B
C
D
A
B
C]
and so on......

 Réponse acceptée

A=randi(10,4,3)
A = 4×3
10 2 9 7 7 4 10 5 1 5 9 2
B=randi(10,5,3)
B = 5×3
8 6 1 10 1 9 6 5 9 5 8 8 10 3 3
C=randi(10,6,3)
C = 6×3
1 6 4 9 4 2 7 5 6 9 5 4 3 2 5 1 2 7
D=randi(10,7,3)
D = 7×3
5 8 3 4 9 5 5 3 9 6 7 7 4 9 3 8 5 6 7 9 9
N=2;
newMatrix=generateMatrix(A,B,C,D,N)
newMatrix = 15×3
10 2 9 7 7 4 10 5 1 5 9 2 8 6 1 10 1 9 6 5 9 5 8 8 10 3 3 1 6 4
function newMatrix=generateMatrix(A,B,C,D,N)
n=2*N-1;
s=[size(A,1),size(B,1),size(C,1),size(D,1)];
newMatrix=repmat([A;B;C;D],ceil(n/4),1);
S=sum(s*floor(n/4))+sum(s(1:mod(n,4)));
newMatrix=newMatrix(1:S,:);
end

Plus de réponses (1)

KALYAN ACHARJYA
KALYAN ACHARJYA le 28 Oct 2022
Modifié(e) : KALYAN ACHARJYA le 28 Oct 2022
% Just example
A=rand(4,3);
B=rand(4,3);
C=rand(4,3);
D=rand(4,3);
data_mat={A,B,C,D}; % Created to handle data easily
N=4 ; % Example or length of data_mat
data=cell(1,N); %Memory Pre-allocation
for i=1:N
data{i}=horzcat(data_mat{1:i});
end
data
data = 1×4 cell array
{4×3 double} {4×6 double} {4×9 double} {4×12 double}
You may look for cellfun also, please do the modification as per requirements.

2 commentaires

KALYAN ACHARJYA
KALYAN ACHARJYA le 28 Oct 2022
To store matrix or any other data type, cell array is much easier way to handle it.
Hope it helps!
Akshay Sahu
Akshay Sahu le 29 Oct 2022
Yes, It's also correct for N=4. But N is not constant in my case. I want to change value of N according to my need.

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