How can I a function on the interval

I got a equation: x+ln x = 0, and I want to plot it on the interval [0.1, 1]

I have tried this code:

f = @(x)x+log(x)

f = function_handle with value:
    @(x)x+log(x)

fplot(f,[0.1 1])

But it only shows: f =

function_handle with value:

@(x)x+log(x)

Is anything wrong with my code? Thank you!

[Torsten]

You didn't set a

;

at the end of the line

f = @(x)x+log(x)

So f is displayed.

But the plot follows - so everything is fine.

Answer 1

[Star Strider]

If you want the x and y values, you need to ask for them —

f = @(x)x+log(x)

f = function_handle with value:
    @(x)x+log(x)

hfp = fplot(f,[0.1 1]);

x = hfp.XData

x = 1×47

0.1000 0.1094 0.1188 0.1298 0.1409 0.1623 0.1818 0.2019 0.2227 0.2453 0.2636 0.2864 0.3045 0.3243 0.3455 0.3651 0.3864 0.4092 0.4273 0.4492 0.4682 0.4897 0.5091 0.5294 0.5500 0.5705 0.5909 0.6122 0.6318 0.6539

y = hfp.YData

y = 1×47

-2.2026 -2.1035 -2.0118 -1.9116 -1.8187 -1.6558 -1.5229 -1.3982 -1.2791 -1.1600 -1.0695 -0.9638 -0.8844 -0.8019 -0.7174 -0.6424 -0.5646 -0.4844 -0.4231 -0.3511 -0.2907 -0.2242 -0.1660 -0.1067 -0.0478 0.0091 0.0648 0.1214 0.1727 0.2291

.