Counting occurrence of elements in an array

How would I go about counting the occurrence of elements in an array including elements that may not be in the array.

For example if x = [2 3 2 4 5 6 8 2 9 5], I would like to produce an array that has the frequency of each element from 1 to 10 so it'd be output = [0 3 1 1 2 1 0 1 1 0]

Thanks

Answer 1

[Star Strider]

Use the hist function:

x = [2 3 2 4 5 6 8 2 9 5];
binc = [1:10];
counts = hist(x,binc);
result = [binc; counts]

produces:

result =

       1     2     3     4     5     6     7     8     9    10
       0     3     1     1     2     1     0     1     1     0

[AB WAHEED LONE]

That is great.

It works

Answer 2

[Ryan]

This works....

x= [2 3 2 4 5 6 8 2 9 5]

for index=1:length(x)
    y(index)= sum(x==index);
end

y

produces

x =

       2     3     2     4     5     6     8     2     9     5

y =

       0     3     1     1     2     1     0     1     1     0

[Katherine May]

This also works for array items that aren't numbers!