Converting cell in double

Hey Guys,

i have a 8942x1 cell and want to convert it into a 8942x1 double ? The final product should be look likes this:

[] 0

1 1

[] => 0

[] 0

[] 0

... ...

Thank you very much for your help!

Attached my file:

Answer 1

[Star Strider]

Try something like this —

LD = load(websave('ids','https://www.mathworks.com/matlabcentral/answers/uploaded_files/1249257/ids.mat'));
ids = LD.ids

ids = 8942×1 cell array
    {0×0 double}
    {[       1]}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}

idsd = cell2mat(ids)

idsd = 966×1

1 1 1 1 1 1 1 1 1 1

idsmt = cellfun(@isempty,ids, 'Unif',0);                        % Detect Empty Cells
ids(cell2mat(idsmt)) = {0};                                     % Fill Missing Values With '0'
idsd = cell2mat(ids)

idsd = 8942×1

0 1 0 0 0 0 0 0 0 0

EDIT — Corrected typographical errors.

.

[Max1234]

Perfect!! Thank you!

[Star Strider]

As always, my pleasure!

Answer 2

[Stephen23]

Simpler and more efficient:

S = load('ids.mat');
ids = S.ids

ids = 8942×1 cell array
    {0×0 double}
    {[       1]}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}
    {0×0 double}

Method one: robust indexing:

X = cellfun(@isscalar,ids);
V = zeros(size(ids));
V(X) = [ids{X}]

V = 8942×1

0 1 0 0 0 0 0 0 0 0

Method two: VERTCAT():

ids(~cellfun(@isscalar,ids)) = {0};
V = vertcat(ids{:})

V = 8942×1

0 1 0 0 0 0 0 0 0 0