Combine different size matrix

23 vues (au cours des 30 derniers jours)
Fabian Haslwanter
Fabian Haslwanter le 9 Jan 2023
I have 4 Matrices (4 is a Value but should be handled as a matrix):
A = [1 1 1;1 1 1;1 1 1];
B = [2 2 2;2 2 2];
C = [3 3 3];
D = [4];
vertcat(A,C,B)
ans = 6×3
1 1 1 1 1 1 1 1 1 3 3 3 2 2 2 2 2 2
They should be aligned somewhat like this:
syms A
syms B
syms C
syms D
Matrix = [0 D 0 A;0 0 D C;D 0 0 B]
Matrix = 
The right side i did with vertcat as shown above. However, i am struggling with Adding D. When its like in the 1. and 3. row, and A/B are 3/2 Row Matrices, D should become a diagonal matrix. Rest filled with 0. When its a single row like C, its just a single Value. So the final result looks like this:
Result = [0 0 4 0 0 0 1 1 1;0 0 0 4 0 0 1 1 1;0 0 0 0 4 0 1 1 1;0 0 0 0 0 4 3 3 3;4 0 0 0 0 0 2 2 2;0 4 0 0 0 0 2 2 2]
Result = 6×9
0 0 4 0 0 0 1 1 1 0 0 0 4 0 0 1 1 1 0 0 0 0 4 0 1 1 1 0 0 0 0 0 4 3 3 3 4 0 0 0 0 0 2 2 2 0 4 0 0 0 0 2 2 2
It should be done for multiple different cases, so an "automatic" way would be great.
Thank you very much!

Réponse acceptée

Stephen23
Stephen23 le 9 Jan 2023
Modifié(e) : Stephen23 le 9 Jan 2023
Works for any data sets, you just need to specify the column/row order of the matrices:
C = {[1,1,1;1,1,1;1,1,1];[2,2,2;2,2,2];[3,3,3]}; % matrices A,B,C, ...etc
[~,Xc] = ismember('BAC','ABC'); % col order
[~,Xr] = ismember('ACB','ABC'); % row order
D = 4; % scalar
R = cellfun('size',C,1);
[~,Yr] = sort(repelem(Xr(Xc),R(Xc)));
M = D*eye(sum(R));
M = [M(Yr,:),vertcat(C{Xr})]
M = 6×9
0 0 4 0 0 0 1 1 1 0 0 0 4 0 0 1 1 1 0 0 0 0 4 0 1 1 1 0 0 0 0 0 4 3 3 3 4 0 0 0 0 0 2 2 2 0 4 0 0 0 0 2 2 2

Plus de réponses (2)

KSSV
KSSV le 9 Jan 2023
Modifié(e) : KSSV le 9 Jan 2023
A = [1 1 1;1 1 1;1 1 1];
B = [2 2 2;2 2 2];
C = [3 3 3];
D = 4;
iwant = [diag(repmat(D,1,4),2) vertcat(A,C,B)] ;
iwant([5 12]) = D
iwant = 6×9
0 0 4 0 0 0 1 1 1 0 0 0 4 0 0 1 1 1 0 0 0 0 4 0 1 1 1 0 0 0 0 0 4 3 3 3 4 0 0 0 0 0 2 2 2 0 4 0 0 0 0 2 2 2
  3 commentaires
Bjorn Gustavsson
Bjorn Gustavsson le 9 Jan 2023
@Fabian Haslwanter, you should think of the different blocks as individual matrices, and then depending on what ordering you want you should build them the corresponding sizes. If you take an intermediate step for thinking you get:
syms A B C D1 D2 D3 zA1 zA2 zB1 zB2 zC1 zC2
Matrix = [zA1,D1,zA2,A;zB1,zB2,D2,B;D3,zC1,zC2,C];
Frome there you should be able to figure out what lengths you need to expand your scalar (?) D to in the different diagonal-matrices, and what sizes you need for the different zero-blocks. I think I got the first block of rows right in my answer. It should be doable to expand that snippet without too much sweat.
Fabian Haslwanter
Fabian Haslwanter le 9 Jan 2023
@Bjorn Gustavsson thank you very much. I was just working on your idea and wanted to wait until I made it to give you feedback. But I get the idea :D

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Bjorn Gustavsson
Bjorn Gustavsson le 9 Jan 2023
If your D is a scalar that you want to expand into a diagonal matrix then perhaps you can do something along these lines:
szA = size(A);
szB = size(B);
szC = size(C);
szD = size(D);
Matrix = [zeros(szA(1),szB(2)) diag(repmat(D,szA(1))) zeros(szA(1),szC(2)) A];
and so on for the other rows. It is a bit fidgety, but this should set you on the right path.
HTH

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