Effacer les filtres
Effacer les filtres

How to select, or filter, the external border/boundary in a set of (x,y)-points? [Part 2]

6 vues (au cours des 30 derniers jours)
Hi, in a previous question, I asked about a method to obtain the external border from a set of points.
I then tried to apply the same method, proposed by @Dyuman Joshi, i.e.
% Obtain coordinates corresponding to outside border by performing
% exclusive OR on the data, between "border b1" and "border b2":
z = setxor(b1,b2,'rows','stable');
to a larger dataset, that composes numerous "borders". The larger dataset is the following (here attached as well):
% load borders and plot them
load('borders2.mat','a')
figure; hold on
for i = 1 : length(a)
line(a{i}(:,1),a{i}(:,2),'color','k');
end
hold off
When I tried to use iteratively the method proposed by @Dyuman Joshi, I got a wrong output (and stuck) and I do not know how to solve the issue.. any idea or suggestion?
% remove iteratively "common edges", and plot the external common border
figure; hold on
b=a{1};
for i = 2 : length(a)
c=a{i};
b=setxor(b,c,'rows','stable');
plot(b(:,1),b(:,2),'r')
end
hold off
Note: as alternative method, I also tried to use the boundary function, with the maximum shrinking factor, but, still, it does not follow the exact shape of the external common border (as I would like).
  2 commentaires
Dyuman Joshi
Dyuman Joshi le 12 Juil 2023
The points that still appear on the inside (of outer boundary) are the points of intersection of 3 or more borders, which makes sense.
One approach would be to eliminate the intersection points (as mentioned below) before processing the data via for loop, but that seems difficult to implement.
I'll keep you updated if I find a solution.
load('borders2.mat','a')
figure
hold on
for i = 1 : length(a)
line(a{i}(:,1),a{i}(:,2),'color','k');
end
%a = cellfun(@(x) unique(x,'rows', 'stable'), a, 'uni', 0);
b=a{1};
for i = 2:numel(a)
c=a{i};
b=setxor(b,c,'rows','stable');
end
plot(b(:,1),b(:,2),'ro ','MarkerSize',5)
Sim
Sim le 12 Juil 2023
Modifié(e) : Sim le 12 Juil 2023
Many thanks @Dyuman Joshi!! And thanks a lot to @Kanishk Singhal for the precious suggestions!
I did not notice that the "internal" points, that remain after using setxor, are the points of intersection of 3 or more borders..! Good to know.. :-) I am also trying to remove them... Yes, in case you find a suitable way to remove them please let me know! I will also write a possible solution here, if I am able to get it :-)

Connectez-vous pour commenter.

Réponse acceptée

Bruno Luong
Bruno Luong le 12 Juil 2023
Modifié(e) : Bruno Luong le 12 Juil 2023
Use the right tool: polyshape class
load('borders2.mat')
n = length(a);
warning('off','MATLAB:polyshape:repairedBySimplify')
Q = polyshape(zeros(0,2));
for k=1:n
Q = union(polyshape(a{k}),Q);
end
plot(Q)
  9 commentaires
Bruno Luong
Bruno Luong le 12 Juil 2023
IMHO it requires quite a bit of programming and reflexion. Your attemps seem too quick to be effective.
Sim
Sim le 12 Juil 2023
Modifié(e) : Sim le 12 Juil 2023
OK, thanks :-) ...btw, it is 2-3 days I am trying to find a solution for this task... :-)

Connectez-vous pour commenter.

Plus de réponses (1)

Kanishk Singhal
Kanishk Singhal le 11 Juil 2023
If you plot after the loop,
figure; hold on
b=a{1};
for i = 2 : length(a)
c=a{i};
b=setxor(b,c,'rows','stable');
end
plot(b(:,1),b(:,2), '.')
hold off
you will get a plot like this.
Most boundary is removed but this the data is not perfect, some points which are inside are must be shared at unique to a cell.
Here you have two possibilities,
  1. Either clean the data remove these points or add these points in another cell.
  2. You get all the points from b, plot the points but make some kind of distance function which can identify these points.
In my opinion cleaning the data is a better option.
  2 commentaires
Sim
Sim le 11 Juil 2023
Modifié(e) : Sim le 11 Juil 2023
Thanks a lot @Kanishk Singhal! With the points2contour function (by @Tristan Ursell), I tried to sort the (x,y)-coordinates of the entire dataset, in order to get the external border (despite the internal points) and I got this:
figure;
b=a{1};
for i = 2 : length(a)
c=a{i};
b=setxor(b,c,'rows','stable');
end
[Xout,Yout]=points2contour(b(:,1),b(:,2),1,'cw'); % sort (x,y)-coordinates
plot([Xout Xout(1)],[Yout Yout(1)],'.-','color','r','MarkerFaceColor','r','MarkerEdgeColor','r') % after sorting
Then, I tried to remove the points that are quite distant from other ones, in order to remove the internal ones, but it did not work well....
% clean and plot
threshold_distance=1300;
[row,~]=ind2sub(size(b),find(abs(diff(b))>threshold_distance));
b(row,:)=[];
[Xout,Yout]=points2contour(b(:,1),b(:,2),1,'cw');
figure
plot([Xout Xout(1)],[Yout Yout(1)],'.-','color','r','MarkerFaceColor','r','MarkerEdgeColor','r')
Sim
Sim le 11 Juil 2023
Modifié(e) : Sim le 11 Juil 2023
If we follow the approach of directly take the boundary, I found some workaround, even though I am not super happy with that approach....indeed, for me, the best would have been what I did in my previous comment, but I am not able to clear the internal points in a proper way...
The workaround would be to use the Boundary extraction (identification and tracing) from point cloud data function (with a tiny modification about the output - see here attached the file I used), based on delaunay triangulation (that I then compared with the default boudary function of Matlab)
clear all;close all; clc;
shrink_factor = 1;
points_distance = 1000;
load('borders2.mat')
b=vertcat(a{:});
[X,bids,E,Ne] = find_delaunay_boundary03_noAngleThreshold(b,points_distance);
figure;
hold on
plot(X(:,1),X(:,2),'.b','MarkerSize',1);
plot(X(:,1),X(:,2),'ok','MarkerSize',1);
for i=1:size(bids,2)
bndry = X(bids{i},:);
p1=plot(bndry(:,1),bndry(:,2),'-r','LineWidth',2); hold on;
end
k=boundary(b(:,1),b(:,2),shrink_factor);
p2=plot(b(k,1),b(k,2),'b','LineWidth',2);
hold off;
legend([p1 p2],{'delaunay boundary','default boundary'},'Location','northwest')

Connectez-vous pour commenter.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by